1
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$\lim _\limits{x \rightarrow \frac{\pi}{2}} \frac{\cot x-\cos x}{(\pi-2 x)^3}$$ equals

A
$$\frac{1}{24}$$
B
$$\frac{1}{16}$$
C
$$\frac{1}{8}$$
D
$$\frac{1}{4}$$
2
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\matrix{ {f(x) = a{x^2} + bx + 1,} & {if} & {\left| {2x - 3} \right| \ge 2} \cr { = 3x + 2,} & {if} & {{1 \over 2} < x < {5 \over 2}} \cr } $$

is continuous on its domain, then $$a+b$$ has the value

A
$$\frac{13}{5}$$
B
$$\frac{31}{5}$$
C
$$\frac{23}{5}$$
D
$$\frac{1}{5}$$
3
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$\lim _\limits{x \rightarrow 1} \frac{x^2-a x+b}{(x-1)}=5$$, then $$(a+b)$$ is equal to

A
$$-$$4
B
$$-$$7
C
7
D
$$-$$3
4
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let

$$\begin{aligned} f(x) & =x+a \sqrt{2} \sin x & & , 0 \leq x<\frac{\pi}{4} \\ & =2 x \cot x+b & & \frac{\pi}{4} \leq x<\frac{\pi}{2} \\ & =a \cos 2 x-b \sin x & & \frac{\pi}{2} \leq x \leq \pi \end{aligned}$$

If $$\mathrm{f}(\mathrm{x})$$ is continuous for $$0 \leq \mathrm{x} \leq \pi$$, then

A
$$a=\frac{\pi}{6}, b=\frac{\pi}{12}$$
B
$$\mathrm{a}=\frac{-\pi}{6}, \mathrm{~b}=\frac{-\pi}{12}$$
C
$$a=\frac{-\pi}{6}, b=\frac{\pi}{12}$$
D
$$a=\frac{\pi}{6}, b=\frac{-\pi}{12}$$
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