1
IIT-JEE 2002 Screening
+2
-0.5
The point(s) in the curve $${y^3} + 3{x^2} = 12y$$ where the tangent is vertical, is (are)
A
$$\left( { \pm {4 \over {\sqrt 3 }}, - 2} \right)$$
B
$$\left( { \pm \sqrt {{{11} \over 3}} ,1} \right)$$
C
$$(0,0)$$
D
$$\left( { \pm {4 \over {\sqrt 3 }}, 2} \right)$$
2
IIT-JEE 2001 Screening
+2
-0.5
If $$f\left( x \right) = x{e^{x\left( {1 - x} \right)}},$$ then $$f(x)$$ is
A
increasing on $$\left[ { - 1/2,1} \right]$$
B
decreasing on $$R$$
C
increasing on $$R$$
D
decreasing on $$\left[ { - 1/2,1} \right]$$
3
IIT-JEE 2001 Screening
+2
-0.5
The triangle formed by the tangent to the curve $$f\left( x \right) = {x^2} + bx - b$$ at the point $$(1, 1)$$ and the coordinate axex, lies in the first quadrant. If its area is $$2$$, then the value of $$b$$ is
A
$$-1$$
B
$$3$$
C
$$-3$$
D
$$1$$
4
IIT-JEE 2001 Screening
+2
-0.5
Let $$f\left( x \right) = \left( {1 + {b^2}} \right){x^2} + 2bx + 1$$ and let $$m(b)$$ be the minimum value of $$f(x)$$. As $$b$$ varies, the range of $$m(b)$$ is
A
$$\left[ {0,1} \right]$$
B
$$\left( {0,\,1/2} \right]$$
C
$$\left[ {1/2,\,1} \right]$$
D
$$\left( {0,\,1} \right]$$
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