1
IIT-JEE 1998
+2
-0.5
The number of values of $$x$$ where the function
$$f\left( x \right) = \cos x + \cos \left( {\sqrt 2 x} \right)$$ attains its maximum is
A
$$0$$
B
$$1$$
C
$$2$$
D
infinite
2
IIT-JEE 1998
+2
-0.5
If $$f\left( x \right) = {{{x^2} - 1} \over {{x^2} + 1}},$$ for every real number $$x$$, then the minimum value of $$f$$
A
does not exist because $$f$$ is unbounded
B
is not attained even though $$f$$ is bounded
C
is equal to 1
D
is equal to -1
3
IIT-JEE 1997
+2
-0.5
If $$f\left( x \right) = {x \over {\sin x}}$$ and $$g\left( x \right) = {x \over {\tan x}}$$, where $$0 < x \le 1$$, then in this interval
A
both $$f(x)$$ and $$g(x)$$ are increasing functions
B
both $$f(x)$$ and $$g(x)$$ are decreasing functions
C
$$f(x)$$ is an increasing functions
D
$$g(x)$$ is an increasing functions
4
IIT-JEE 1995 Screening
+1
-0.25
The function $$f\left( x \right) = {{in\,\left( {\pi + x} \right)} \over {in\,\left( {e + x} \right)}}$$ is
A
increasing on $$\left( {0,\infty } \right)$$
B
decreasing on $$\left( {0,\infty } \right)$$
C
increasing on $$\left( {0,\pi /e} \right),$$ decreasing on $$\left( {\pi /e,\infty } \right)$$
D
decreasing on $$\left( {0,\pi /e} \right),$$ increasing on $$\left( {\pi /e,\infty } \right)$$
EXAM MAP
Medical
NEET