IIT-JEE 2005 Screening | Ellipse Question 25 | Mathematics

IIT-JEE 2005 Screening

MCQ (Single Correct Answer)

-0.5

The minimum area of triangle formed by the tangent to the $${{{x^2}} \over {{a^2}}} + {{{y^2}} \over {{b^2}}} = 1$$ and coordinate axes is

$$ab$$ sq. units

$${{{{a^2} + {b^2}} \over 2}}$$ sq. units

$${{{{\left( {a + b} \right)}^2}} \over 2}$$ sq. units

$${{{a^2} + ab + {b^2}} \over 3}$$ sq. units

IIT-JEE 2004 Screening

MCQ (Single Correct Answer)

-0.5

If tangents are drawn to the ellipse $${x^2} + 2{y^2} = 2,$$ then the locus of the mid-point of the intercept made by the tangents between the coordinate axes is

$${1 \over {2{x^2}}} + {1 \over {4{y^2}}} = 1$$

$${1 \over {4{x^2}}} + {1 \over {2{y^2}}} = 1$$

$${{{x^2}} \over 2} + {{{y^2}} \over 4} = 1$$

$${{{x^2}} \over 4} + {{{y^2}} \over 2} = 1$$

IIT-JEE 2003 Screening

MCQ (Single Correct Answer)

-0.5

The area of the quadrilateral formed by the tangents at the end points of latus rectum to the ellipse $${{{x^2}} \over 9} + {{{y^2}} \over 5} = 1,$$ is

$$27/4$$ sq. units

$$9$$ sq. units

$$27/2$$ sq. units

$$27$$ sq. units

IIT-JEE 1998

MCQ (Single Correct Answer)

-0.5

If $$P=(x, y)$$, $${F_1} = \left( {3,0} \right),\,{F_2} = \left( { - 3,0} \right)$$ and $$16{x^2} + 25{y^2} = 400,$$ then $$P{F_1} + P{F_2}$$ equals

$$8$$

$$6$$

$$10$$

$$12$$

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