1
MHT CET 2024 2nd May Evening Shift
MCQ (Single Correct Answer)
+2
-0

$\lim _\limits{x \rightarrow 0} \frac{\sin \left(\pi \cos ^2 x\right)}{x^2}$ is equal to

A
1
B
$-\pi$
C
$\pi$
D
$\frac{\pi}{2}$
2
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The value of $\lim _\limits{x \rightarrow 0} \frac{x}{|x|+x^2}$ is

A
1
B
$-1$
C
0
D
does not exist
3
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{f}(x)=\frac{1+\cos \pi x}{\pi(1-x)^2}$, for $x \neq 1$ is continuous at $x=1$, then $\mathrm{f}(1)$ is equal to

A
$\frac{\pi}{2}$
B
$\frac{2}{\pi}$
C
$\frac{\pi^2}{4}$
D
$\frac{4}{\pi^2}$
4
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Let K be the set of all real values of $x$, where the function $\mathrm{f}(x)=\sin |x|-|x|+2(x-\pi) \cos |x|$ is not differentiable. Then the set K is

A
$\{0\}$
B
an empty set
C
$\{\pi\}$
D
$\{0, \pi\}$
MHT CET Subjects
EXAM MAP