1
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
MHT CET 2026 18th April Morning Shift Physics - Simple Harmonic Motion Question 18 English
All the springs in fig (a), (b) and (c) are identical, each one having force constant K. Mass m is attached to each system. If $T_a$, $T_b$ and $T_c$ are the periodic time of oscillations of the three systems in fig (a), (b) and (c) respectively, then
A
$T_a = \sqrt{2}\,T_b$
B
$T_b = 2T_a$
C
$T_a = \dfrac{T_c}{\sqrt{2}}$
D
$T_b = 2T_c$
2
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A particle is performing simple harmonic motion about $x = 0$ with an amplitude '$a$' and periodic time T. The speed of the particle at $x = \dfrac{a}{3}$ will be
A
$\dfrac{2\pi a}{T}$
B
$\dfrac{4\pi a}{3T}$
C
$\dfrac{4\sqrt{2}\,\pi a}{3T}$
D
$\dfrac{\sqrt{3}\,\pi^2 a}{2T}$
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
The displacement of a particle performing linear S.H.M. is given by $y = A\cos[\pi(t + \phi)]$. If at $t = 0$, the displacement is $y = 2$ cm and velocity is $2\pi$ cm/s, the value of amplitude A in cm is
A
$\dfrac{1}{\sqrt{2}}$
B
$\sqrt{2}$
C
$2$
D
$2\sqrt{2}$
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A light spring is suspended with mass '$m_1$' at its lower end and its upper end is fixed to a rigid support. The mass is pulled down a short distance and then released. The period of oscillation is T second. When a mass '$m_2$' is added to '$m_1$' and the system is made to oscillate the period is found to be $\dfrac{3}{2}$ T. The ratio $\left(\dfrac{m_1}{m_2}\right)$ is
A
$2 : 3$
B
$3 : 4$
C
$4 : 5$
D
$5 : 6$

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