1
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum of length $$L$$ has mass $$m$$ and it oscillates freely with amplitude $$A$$. At extreme position, its potential energy is ($$g=$$ acceleration due to gravity)

A
$$\frac{m g A}{L}$$
B
$$\frac{m g A}{2 l}$$
C
$$\frac{m g A^2}{L}$$
D
$$\frac{m g A^2}{2 L}$$
2
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+1
-0

For a particle performing SHM when displacement is $$x$$, the potential energy and restoring force acting on it is denoted by $$E$$ and $$F$$, respectively. The relation between $$x, E$$ and $$F$$ is

A
$$\frac{E}{F}+x=0$$
B
$$\frac{2 E}{F}-x=0$$
C
$$\frac{2 E}{F}+x=0$$
D
$$\frac{E}{F}-x=0$$
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