MHT CET 2023 13th May Evening Shift | Simple Harmonic Motion Question 46 | Physics

Under the influence of force $$F_1$$ the body oscillates with a period $$T_1$$ and due to another force $$F_2$$ body oscillates with period $$T_2$$. If both forces acts simultaneously, then the resultant period is (consider displacement is same in all three cases)

$$T=\sqrt{\frac{T_1^2+T_2^2}{T_1^2 T_2^2}}$$

$$T=\sqrt{\frac{T_1^2 T_2^2}{T_1^2+T_2^2}}$$

$$T=\sqrt{\frac{T_1^2}{T_2^2}}$$

$$T=\sqrt{T_1^2+T_2^2}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

A mass $$M$$ is suspended from a light spring. An additional mass $$M_1$$ added extends the spring further by a distance $$x$$. Now, the combined mass will oscillate on the spring with period $$T=$$

$$2 \pi\left[\left(\frac{M_1 g}{x\left(M+M_1\right)}\right)\right]^{\frac{1}{2}}$$

$$2 \pi\left[\frac{\left(M+M_1\right) x}{M_1 g}\right]^{\frac{1}{2}}$$

$$\left(\frac{\pi}{2}\right)\left[\left(\frac{M_1 g}{x\left(M+M_1\right)}\right)\right]^{\frac{1}{2}}$$

$$2 \pi\left[\left(\frac{M+M_1}{M_1 g x}\right)\right]^{\frac{1}{2}}$$

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

A body of mass $$0.04 \mathrm{~kg}$$ executes simple harmonic motion (SHM) about $$\mathrm{x}=0$$ under the influence of force $$\mathrm{F}$$ as shown in graph. The period of

MHT CET 2023 13th May Morning Shift Physics - Simple Harmonic Motion Question 78 English

$$2 \pi \mathrm{s}$$

$$0.2 \pi \mathrm{s}$$

$$\pi \mathrm{d}$$

$$\frac{\pi}{2} \mathrm{~s}$$

MHT CET 2023 13th May Morning Shift

MCQ (Single Correct Answer)

-0

A simple pendulum has a time period '$$T$$' in air. Its time period when it is completely immersed in a liquid of density one eighth the density of the material of bob is

$$\left(\sqrt{\frac{7}{8}}\right) \mathrm{T}$$

$$\left(\sqrt{\frac{5}{8}}\right) \mathrm{T}$$

$$\left(\sqrt{\frac{3}{8}}\right) \mathrm{T}$$

$$\left(\sqrt{\frac{8}{7}}\right) \mathrm{T}$$

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