1
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The graph shows the variation of voltage ' V ' across the plates of two capacitors $A$ and $B$ versus increase in charge ' $Q$ ' stored in them. Then

A
capacitance A has high capacity.
B
capacitance B has high capacity.
C
both have same capacity.
D
capacity of $A=2$ times capacity of $B$.
2
MHT CET 2024 16th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Air capacitor has capacitance ' $\mathrm{C}_1$ '. The space between two plates of capacitor is filled with two dielectrics as shown in figure. The new capacitance of the capacitor is ' $\mathrm{C}_2$ '. The ratio $\frac{C_1}{C_2}$ is $(d=$ distance between two plates of capacitor, $\mathrm{K}_1$ and $\mathrm{K}_2$ are dielectric constants of two dielectrics respectively)

A
$\mathrm{K}_1+\mathrm{K}_2$
B
$\frac{\mathrm{K}_1+\mathrm{K}_2}{\mathrm{~K}_1-\mathrm{K}_2}$
C
$\frac{2 \mathrm{~K}_1 \mathrm{~K}_2}{\mathrm{~K}_1+\mathrm{K}_2}$
D
$\frac{\mathrm{K}_1+\mathrm{K}_2}{2 \mathrm{~K}_1 \mathrm{~K}_2}$
3
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
 

Two identical capacitors A and B are connected in series to a battery of E.M.F., 'E'. Capacitor B contains a slab of dielectric constant $\mathrm{K} . \mathrm{Q}_{\mathrm{A}}$ and $\mathrm{Q}_{\mathrm{B}}$ are the charges stored in A and B . When the dielectric slab is removed, the corresponding charges are $\mathrm{Q}_{\mathrm{A}}^{\prime}$ and $\mathrm{Q}_{\mathrm{B}}^{\prime}$. Then

A
$\mathrm{\frac{Q_A^{\prime}}{Q_A}=\frac{K}{2}}$
B
$\frac{\mathrm{Q}_{\mathrm{B}}^{\prime}}{\mathrm{Q}_{\mathrm{B}}}=\frac{\mathrm{K}+1}{2}$
C
$\frac{\mathrm{Q}_{\mathrm{A}}^{\prime}}{\mathrm{Q}_{\mathrm{A}}}=\frac{\mathrm{K}+1}{\mathrm{~K}}$
D
$\frac{\mathrm{Q}_{\mathrm{B}}^{\prime}}{\mathrm{Q}_{\mathrm{B}}}=\frac{\mathrm{K}+1}{2 \mathrm{~K}}$
4
MHT CET 2024 16th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A series combination of $n_1$ capacitors, each of value $C_1$ is charged by a source of potential difference 6 V . Another parallel combination of $\mathrm{n}_2$ capacitors, each of value $\mathrm{C}_2$ is charged by a source of potential difference 2 V . Total energy of both the combinations is same. The value of $\mathrm{C}_2$ in terms of $\mathrm{C}_1$ is

A
$\frac{3 C_1}{n_1 n_2}$
B
$\frac{9 \mathrm{n}_2}{\mathrm{n}_1} \mathrm{C}_1$
C
$\frac{3 \mathrm{n}_2}{\mathrm{n}_1} \mathrm{C}_1$
D
$\frac{9 C_1}{n_1 n_2}$
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