1
MHT CET 2025 22nd April Evening Shift
MCQ (Single Correct Answer)
+1
-0

Initially $n$ identical capacitors are joined in parallel and are charged to potential V. Now they are separated and joined in series. Then

A
potential difference and total energy of the combination remain the same.
B
potential difference remains the same and energy increases n times.
C
potential difference becomes nV and energy remains the same.
D
potential difference is nV and energy increases n times.
2
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

A series combination of 10 capacitors, each of value ' $\mathrm{C}_1$ ' is charged by a source of potential difference ' 4 V '. When another parallel combination of 8 capacitors, each of value ' $\mathrm{C}_2$ ' is charged by a source of potential difference ' V ', it has the same total energy stored in it as in the first combination. The value of ' $\mathrm{C}_2$ ' is

A
$\frac{\mathrm{C}_1}{5}$
B
$\frac{8}{5} \mathrm{C}_1$
C
$\frac{64}{5} C_1$
D
$\frac{\mathrm{C}_1}{40}$
3
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

The graph shows the variation of voltage (v) across the plates of two parallel plate capacitos $A$ and $B$ versus increase of charge $Q$ stored in them. Then

MHT CET 2025 22nd April Morning Shift Physics - Capacitor Question 1 English
A
capacity of both capacitors is same.
B
capacity of $A$ is higher than $B$.
C
capacity of $B$ is higher than $A$.
D
capacity of both is zero.
4
MHT CET 2025 22nd April Morning Shift
MCQ (Single Correct Answer)
+1
-0

Three capacitors each of capacitance ' C ' and breakdown voltage ' $V$ ' are connected in series. The capacitance and breakdown voltage of the series combination will be respectively

A
$3 \mathrm{C}, 3 \mathrm{~V}$
B
$\frac{\mathrm{C}}{3}, \frac{\mathrm{~V}}{3}$
C
$3 \mathrm{C}, \frac{\mathrm{V}}{3}$
D
$\frac{\mathrm{C}}{3}, 3 \mathrm{~V}$
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