MHT CET 2024 3rd May Evening Shift | Simple Harmonic Motion Question 69 | Physics

Frequency of a particle performing S.H.M. is 10 Hz . The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$

$\frac{1}{\pi} \mathrm{~m} / \mathrm{s}$

$\frac{1}{2 \pi} \mathrm{~m} / \mathrm{s}$

$\frac{1}{4 \pi} \mathrm{~m} / \mathrm{s}$

$2 \pi \mathrm{~m} / \mathrm{s}$

MHT CET 2024 3rd May Evening Shift

MCQ (Single Correct Answer)

-0

When a particle in linear S.H.M. completes two oscillations, its phase increases by

$\pi \mathrm{~rad}$.

$2 \pi \mathrm{~rad}$.

$3 \pi \mathrm{~rad}$.

$4 \pi \mathrm{~rad}$.

MHT CET 2024 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

A small sphere oscillates simple harmonically in a watch glass whose radius of curvature is 1.6 m . The period of oscillation of the sphere in second is (acceleration due to gravity, $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )

$0.8 \pi$

$0.6 \pi$

$0.4 \pi$

$0 \cdot 2 \pi$

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