MHT CET 2025 22nd April Evening Shift | Ray Optics Question 1 | Physics

A concave lens (refractive index $=1.5$ ) has both surfaces of same radius of curvature R . If it is immersed in a liquid of refractive index 1.75 it will act as a

concave lens of focal length (3.5) R

concave lens of focal length 2 R .

convex lens of focal length (3.5) R

convex lens of focal length $2 R$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

-0

Two thin lenses having $\mathrm{R}_1, \mathrm{R}_2$ as the radii of curved surfaces are kept coaxially together. Their power is proportional to

$\mathrm{R}_1+\mathrm{R}_2$

$\mathrm{R}_1-\mathrm{R}_2$

$\frac{\mathrm{R}_1 \mathrm{R}_2}{\mathrm{R}_1+\mathrm{R}_2}$

$\frac{R_1+R_2}{R_1 R_2}$

MHT CET 2025 21st April Evening Shift

MCQ (Single Correct Answer)

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A ray of light travelling through rarer medium is incident at a very small angle ' $i$ ' on a glass slab and after refraction its velocity is reduced by $20 \%$. The angle of deviation is

$\frac{\mathrm{i}}{5}$

$\frac{\mathrm{i}}{8}$

$\frac{\mathrm{i}}{4}$

$\frac{\mathrm{i}}{2}$

MHT CET 2025 21st April Evening Shift

MCQ (Single Correct Answer)

-0

A plano convex lens fits exactly in to a plano concave lens. Their plane surfaces are parallel to each other. Lenses are made up of different materials of refractive indices ' $\mathrm{n}_1$ ' ' $\mathrm{n}_2$ ' and ' R ' is the radius of curvature of the curved surface of lenses. Focal length of the combination is

$\frac{\mathrm{R}}{\mathrm{n}_1+\mathrm{n}_2}$

$\frac{2 R}{n_1-n_2}$

$\frac{R}{2\left(n_1-n_2\right)}$

$\frac{R}{n_1-n_2}$

MHT CET Subjects