MHT CET 2021 22th September Evening Shift | Simple Harmonic Motion Question 39 | Physics

A particle connected to the end of a spring executes S.H.M. with period '$$T_1$$'. While the corresponding period for another spring is '$$\mathrm{T}_2$$'. If the period of oscillation with two springs in series is 'T', then

$$\mathrm{T}=\sqrt{\mathrm{T}_1^2+\mathrm{T}_2^2}$$

$$\mathrm{T}=\sqrt{\mathrm{T}_2^2-\mathrm{T}_1^2}$$

$$\mathrm{T=T_1+T_2}$$

$$\mathrm{T}=\mathrm{T}_1-\mathrm{T}_2$$

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

-0

'$$n$$' waves are produced on a string in 1 second. When the radius of the string is doubled, keeping tension same, the number of waves produced in 1 second for the same harmonic will be

$$2 \mathrm{n}$$

$$\frac{\mathrm{n}}{2}$$

$$\frac{\mathrm{n}}{\sqrt{2}}$$

$$\sqrt{2} \mathrm{n}$$

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

-0

A body of mass '$$m$$' performs linear S.H.M. given by equation $$x=P \sin \omega t+Q \sin \left(\omega t+\frac{\pi}{2}\right)$$. The total energy of the particle at any instant is

$$\frac{1}{2} \mathrm{~m} \omega^2 \mathrm{PQ}$$

$$\frac{1}{2} \frac{\mathrm{m} \omega^2}{\mathrm{P}^2 \mathrm{Q}^2}$$

$$\frac{1}{2} m \omega^2\left(P^2+Q^2\right)$$

$$\frac{1}{2} m \omega^2 p^2 Q^2$$

MHT CET 2021 22th September Morning Shift

MCQ (Single Correct Answer)

-0

A mass $$0.4 \mathrm{~kg}$$ performs S.H.M. with a frequency $$\frac{16}{\pi} \mathrm{Hz}$$. At a certain displacement it has kinetic energy $$2 \mathrm{~J}$$ and potential energy $$1.2 \mathrm{~J}$$. The amplitude of oscillation is

$$0.15 \mathrm{~m}$$

$$0.125 \mathrm{~m}$$

$$0.075 \mathrm{~m}$$

$$0.1 \mathrm{~m}$$

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