MHT CET 2024 16th May Evening Shift | Motion Question 1 | Physics

A body travelling with uniform acceleration crosses two points A and B with velocities $20 \mathrm{~m} / \mathrm{s}$ and $30 \mathrm{~m} / \mathrm{s}$ respectively. The speed of the body at mid point of A and B is (nearly)

$25 \mathrm{~m} / \mathrm{s}$

$25.5 \mathrm{~m} / \mathrm{s}$

$24 \mathrm{~m} / \mathrm{s}$

$10 \sqrt{6} \mathrm{~m} / \mathrm{s}$

MHT CET 2024 16th May Morning Shift

MCQ (Single Correct Answer)

-0

The co-ordinates of a moving particle at any time ' $t$ ' are given by $x=\alpha t^3$ and $y=\beta t^3$ where $\alpha$ and $\beta$ are constants. The speed of the particle at time ' $t$ ' is given by

$t \sqrt{\alpha^2+\beta^2}$

$3 t \sqrt{\alpha^2+\beta^2}$

$t^2 \sqrt{\alpha^2+\beta^2}$

$3 t^2 \sqrt{\alpha^2+\beta^2}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

A ball is released from the top of a tower of height Hm . It takes T second to reach the ground. The height of the ball from the ground after $\frac{T}{4}$ second is

$\frac{13 \mathrm{H}}{14}$

$\frac{15 \mathrm{H}}{16}$

$\frac{11 \mathrm{H}}{12}$

$\frac{9 \mathrm{H}}{10}$

MHT CET 2024 11th May Evening Shift

MCQ (Single Correct Answer)

-0

Two cars start from a point at the same time in a straight line and their positions are represented by $x_1(t)=a t+b t^2$ and $x_2(t)=F t-t^2$. At what time do the cars have the same velocity?

$\frac{a+F}{2(b-1)}$

$\frac{a-F}{1+b}$

$\frac{a+F}{2(1+b)}$

$\frac{F-a}{2(1+b)}$

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