MHT CET 2025 5th May Evening Shift | Center of Mass and Collision Question 1 | Physics

A sphere of mass ' $m$ ', moving with velocity ' $3 u$ ' collides head-on with another identical sphere at rest. If ' $e$ ' is coefficient of restitution then what will be the ratio of velocity of the second sphere to that of first sphere after collision?

$\frac{1-\mathrm{e}}{1+\mathrm{e}}$

$\frac{1+\mathrm{e}}{1-\mathrm{e}}$

$\frac{e+1}{e-1}$

$\frac{e-1}{e+1}$

MHT CET 2025 25th April Evening Shift

MCQ (Single Correct Answer)

-0

An object of mass ' $m$ ' moving with velocity ' $u$ ' collides with another stationary object of mass ' $M$ ' and stops just after the collision. The coefficient of restitution is

$\frac{\mathrm{m}}{\mathrm{M}+\mathrm{m}}$

$\frac{M-m}{M+m}$

$\frac{\mathrm{m}}{\mathrm{M}}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

There is head-on elastic collision between the two particles moving in the same direction with speeds $5 \mathrm{~m} / \mathrm{s}$ and $3 \mathrm{~m} / \mathrm{s}$ respectively. After collision, the velocity of the first particle becomes $4 \mathrm{~m} / \mathrm{s}$ in the same direction. The velocity of the second particle should be

$6 \mathrm{~m} / \mathrm{s}$ in the same direction.

$4 \mathrm{~m} / \mathrm{s}$ in the same direction.

$2 \mathrm{~m} / \mathrm{s}$ in the opposite direction.

$3 \mathrm{~m} / \mathrm{s}$ in the same direction.

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Some Basic Concepts of Chemistry Atomic Structure States of Matter Thermodynamics Chemical Equilibrium Ionic Equilibrium Liquid Solution Redox Reactions Surface Chemistry Solid State Electrochemistry Chemical Kinetics Nuclear Chemistry

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