MHT CET 2021 22th September Morning Shift | Simple Harmonic Motion Question 42 | Physics

A mass $$0.4 \mathrm{~kg}$$ performs S.H.M. with a frequency $$\frac{16}{\pi} \mathrm{Hz}$$. At a certain displacement it has kinetic energy $$2 \mathrm{~J}$$ and potential energy $$1.2 \mathrm{~J}$$. The amplitude of oscillation is

$$0.15 \mathrm{~m}$$

$$0.125 \mathrm{~m}$$

$$0.075 \mathrm{~m}$$

$$0.1 \mathrm{~m}$$

MHT CET 2021 22th September Morning Shift

MCQ (Single Correct Answer)

-0

If the amplitude of linear S.H.M. is decreased then

its period and total energy will increase.

its period will increase and total energy will decrease

its period and total energy will decrease.

its period will not change but total energy will decrease

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

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A child is sitting on a swing which performs S.H.M. It has minimum and maximum heights from ground $$0.75 \mathrm{~cm}$$ and $$2 \mathrm{~m}$$ respectively. Its maximum speed will be $$\left[\mathrm{g}=10 \frac{\mathrm{m}}{\mathrm{s}^2}\right]$$

$$\sqrt{1.25} \mathrm{~m} / \mathrm{s}$$

$$\sqrt{12.5} \mathrm{~m} / \mathrm{s}$$

$$5 \mathrm{~m} / \mathrm{s}$$

$$25 \mathrm{~m} / \mathrm{s}$$

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

-0

A pendulum clock is running fast. To correct its time, we should

reduce the mass of the bob.

reduce the amplitude of oscillation.

increase the length of the pendulum.

reduce the length of the pendulum.

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