MHT CET 2024 16th May Morning Shift | Simple Harmonic Motion Question 4 | Physics

A particle executing S.H.M. has velocities ' $\mathrm{V}_1$ ' and ' $\mathrm{V}_2$ ' at distances ' $x_1$ ' and ' $x_2$ ' respectively, from the mean position. Its frequency is

$\frac{1}{2 \pi} \sqrt{\frac{V_1^2-V_2^2}{x_1^2-x_2^2}}$

$2 \pi \sqrt{\frac{x_1^2-x_2^2}{v_1^2-V_2^2}}$

$\frac{1}{2 \pi} \sqrt{\frac{V_2^2-V_1^2}{x_1^2-x_2^2}}$

$2 \pi \sqrt{\frac{\mathrm{x}_1^2-\mathrm{x}_2^2}{\mathrm{~V}_2^2-\mathrm{V}_1^2}}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

For a particle executing S.H.M. having amplitude A, the speed of the article is $\left(\frac{1}{3}\right)^{\text {rd }}$ of its maximum speed when the displacement from the mean position is

$\frac{3 \mathrm{~A}}{\sqrt{2}}$

$\frac{2 \mathrm{~A}}{3}$

$\frac{2 \sqrt{2}}{3} \mathrm{~A}$

$\frac{\sqrt{2}}{3} \mathrm{~A}$

MHT CET 2024 15th May Evening Shift

MCQ (Single Correct Answer)

-0

The motion of a particle is described by the equation $a=-b x$ where ' $a$ ' is the acceleration, x is the displacement from the equilibrium position and b is a constant. The periodic time will be

$\frac{2 \pi}{\mathrm{~b}}$

$\frac{2 \pi}{\sqrt{b}}$

$2 \pi \sqrt{b}$

$2 \sqrt{\frac{\pi}{b}}$

MHT CET 2024 15th May Morning Shift

MCQ (Single Correct Answer)

-0

A horizontal platform with a small object placed on it executes a linear S.H.M. in the vertical direction. The amplitude of oscillation is 40 cm . What should be the least period of these oscillations, so that the object is not detached from the platform? [Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$]

$0.2 \pi \mathrm{~s}$

$0.3 \pi \mathrm{~s}$

$0.4 \pi \mathrm{~s}$

$0.5 \pi \mathrm{~s}$

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