1
GATE ECE 2001
MCQ (Single Correct Answer)
+2
-0.6
In the figure assume the Op-Amps to be ideal. The output V0 of the circuit is GATE ECE 2001 Analog Circuits - Operational Amplifier Question 53 English
A
10 $$\cos $$ (100 t)
B
10 $$\int\limits_0^t {\cos \,\,\left( {100\tau } \right)} \,\,d\tau $$ v
C
$${10^{ - 4}}\int\limits_0^t {\cos \,\,\left( {100\tau } \right)} \,\,d\tau $$
D
$${10^{ - 4}}{d \over {dt}}\cos \left( {100t} \right)$$
2
GATE ECE 2001
MCQ (Single Correct Answer)
+2
-0.6
The Inverting Op-Amp shown in the figure, has an Open-loop gain of 100. The closed loop gain $${{{V_o}} \over {{V_s}}}$$ is GATE ECE 2001 Analog Circuits - Operational Amplifier Question 54 English
A
-8
B
-9
C
-10
D
-11
3
GATE ECE 2001
MCQ (Single Correct Answer)
+2
-0.6
An Amplifier using an Op-Amp with a Slew-Rate SR = V/$$\mu $$sec, has a gain of 40 dB. If this amplifier has to faith fully amplify sinsoidal signals from dc to 20 KHz. Without introducing any Slew Rate induced distortion, then the input signal level must not exceed.
A
795 mV
B
395 mV
C
79.5 mV
D
39.5 mV
4
GATE ECE 2000
MCQ (Single Correct Answer)
+2
-0.6
If the Op-Amp in the figure has an input offset voltage of 5 mV and an open-loop voltage gain of 10,000, V0 will be GATE ECE 2000 Analog Circuits - Operational Amplifier Question 61 English
A
0 V
B
5 mV
C
+ 15 V (or) - 15V
D
+50 V (or) -50V
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