GATE ECE 2014 Set 3 | Uniform Plane Waves Question 18 | Electromagnetics

GATE ECE 2014 Set 3

MCQ (Single Correct Answer)

-0.6

A region shown below contains a perfect conducting half-space and air. The surface current $${\overrightarrow K _{_s}}$$ on the surface of the perfect conductor is $${\overrightarrow K _{_s}} = \widehat x\,2$$ amperes per meter. The tangential $$\overrightarrow H $$ field in the air just above the perfect conductor is GATE ECE 2014 Set 3 Electromagnetics - Uniform Plane Waves Question 24 English

GATE ECE 2014 Set 3 Electromagnetics - Uniform Plane Waves Question 24 English

$$\left( {\widehat x + \widehat z} \right)2$$ amperes per meter

$$\widehat x2$$ amperes per meter

$$ - \widehat z2$$ amperes per meter

$$ \widehat z2$$ amperes per meter

GATE ECE 2014 Set 2

MCQ (Single Correct Answer)

-0.6

If the electric field of a plane wave is $$$\overrightarrow E \left( {z,t} \right) = \widehat x3\cos \left( {\omega t - kz + {{30}^ \circ }} \right) - \widehat y4\sin \left( {\omega t - kz + {{45}^ \circ }} \right)\left( {mV/m} \right)$$$

The polarization state of the plane wave is

left elliptical

left circular

right elliptical

right circular

GATE ECE 2013

MCQ (Single Correct Answer)

-0.6

A monochromatic plane wave of wavelength $$\lambda = 600$$ is propagating in the direction as shown in the figure below. $${\overrightarrow E _i},\,{\overrightarrow E _r}$$ and $${\overrightarrow E _t}$$ denote incident, reflected, and transmitted electric field vectors associated with the wave. GATE ECE 2013 Electromagnetics - Uniform Plane Waves Question 27 English

GATE ECE 2013 Electromagnetics - Uniform Plane Waves Question 27 English

The expression for $${\overrightarrow E _r}$$ is

$$0.23{{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}\left( {x - z} \right)} \over {3\sqrt 2 }}}}\,\,\,V/m$$

$$ - {{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}z} \over 3}}}\,\,\,V/m$$

$$0.44{{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}\left( {x - z} \right)} \over {3\sqrt 2 }}}}\,\,\,V/m$$

$${{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}\left( {x + z} \right)} \over 3}}}\,\,V/m$$

GATE ECE 2013

MCQ (Single Correct Answer)

-0.6

GATE ECE 2013 Electromagnetics - Uniform Plane Waves Question 28 English

The angle of incidence $${\theta _i}$$ and the expression for $${\overrightarrow E _i}$$ are

$${60^ \circ }\,\,\,and\,\,{{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}\left( {x + z} \right)} \over {3\sqrt 2 }}}}\,\,V/m$$

$${45^ \circ }\,\,\,and\,\,{{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}z} \over 3}}}\,\,V/m$$

$${45^ \circ }\,\,\,and\,\,{{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}\left( {x + z} \right)} \over {3\sqrt 2 }}}}\,\,V/m$$

$${60^ \circ }\,\,\,and\,\,{{{E_0}} \over {\sqrt 2 }}\left( {{{\widehat a}_x} - {{\widehat a}_z}} \right){e^{ - j{{\pi \times {{10}^4}z} \over 3}}}\,\,V/m$$

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