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1
JEE Advanced 2016 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
There are two Vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The Vernier scale of one of the calipers (C1) has 10 equal divisions that correspond to 9 main scale divisions. The Vernier scale of the other caliper (C2) has 10 equal divisions that correspond to 11 main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1 and C2 respectively, are

JEE Advanced 2016 Paper 2 Offline Physics - Units & Measurements Question 46 English
A
2.85 and 2.82
B
2.87 and 2.83
C
2.87 and 2.86
D
2.87 and 2.87
2
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Match List I with List II and select the correct answer using the codes given below the lists:

List I

P. Boltzmann Constant
Q. Coefficient of viscosity
R. Plank Constant
S. Thermal conductivity

List II

1. [ML2T-1]
2. [ML-1T-1]
3. [MLT-3K-1]
4. [ML2T-2K-1]
A
$$\eqalign{ & P\,\,\,\,Q\,\,\,\,R\,\,\,\,S \cr & 3\,\,\,\,\,\,1\,\,\,\,\,2\,\,\,\,\,4 \cr} $$
B
$$\eqalign{ & P\,\,\,\,Q\,\,\,\,R\,\,\,\,S \cr & 3\,\,\,\,\,\,2\,\,\,\,\,1\,\,\,\,\,4 \cr} $$
C
$$\eqalign{ & P\,\,\,\,Q\,\,\,\,R\,\,\,\,S \cr & 4\,\,\,\,\,\,2\,\,\,\,\,1\,\,\,\,\,3 \cr} $$
D
$$\eqalign{ & P\,\,\,\,Q\,\,\,\,R\,\,\,\,S \cr & 4\,\,\,\,\,\,1\,\,\,\,\,2\,\,\,\,\,3 \cr} $$
3
JEE Advanced 2013 Paper 1 Offline
MCQ (Single Correct Answer)
+4
-1
The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10 cm and 5.15 cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm. The 24th division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is
A
5.112 cm
B
5.124 cm
C
5.136 cm
D
5.148 cm
4
IIT-JEE 2012 Paper 1 Offline
MCQ (Single Correct Answer)
+4
-1
In the determination of Young's modulus $$\left( {Y = {{4MLg} \over {\pi l{d^2}}}} \right)$$ by using Searle's method, a wire of length L = 2 m and diameter d = 0.5 mm is used. For a load M = 2.5 kg, an extension l = 0.25 mm in the length of the wire is observed. Quantities d and l are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurement
A
due to the errors in the measurements of d and l are the same.
B
due to the error in the measurement of d is twice that due to the error in the measurement of l.
C
due to the error in the measurement of l is twice that due to the error in the measurement of d.
D
due to the error in the measurement of d is four times that due to the error in the measurement of l.

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