JEE Advanced 2013 Paper 2 Offline

MCQ (More than One Correct Answer)

-0.75

Two bodies, each of mass M, are kept fixed with a separation $$2L$$. A particle of mass m is projected from the midpoint of the line joining their centres, perpendicular to the line. The gravitational constant is G. The correct statement(s) is (are)

The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is $$4\sqrt {{{GM} \over L}} $$

The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is $$2\sqrt {{{GM} \over L}} $$

The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is $$\sqrt {{{2GM} \over L}} $$

The energy of the mass m remains constant.

IIT-JEE 2012 Paper 2 Offline

MCQ (More than One Correct Answer)

-1

Two spherical planets P and Q have the same uniform density r, masses M_P and M_Q and surface areas A and 4A respectively. A spherical planet R also has uniform density r and its mass is (M_P + M_Q). The escape velocities from the planets P, Q and R are V_P, V_Q and V_R, respectively. Then

V_Q > V_R > V_P

V_R > V_Q > V_P

$${{{V_R}} \over {{V_P}}} = 3$$

$${{{V_P}} \over {{V_Q}}} = {1 \over 2}$$

JEE Advanced Subjects