1

### IIT-JEE 2000 Screening

The dimension of $\left( {{1 \over 2}} \right){\varepsilon _0}{E^2}$
( ${\varepsilon _0}$ : permittivity of free space, E electric field )
A
MLT-1
B
ML2T-2
C
ML-1T-2
D
ML2T-1

## Explanation

Dimension of $\varepsilon$0 = M$-$1L$-$3T4A2

Dimension of electric field E = MLT$-$3A$-$1

Now, dimension of

${1 \over 2}$$\varepsilon$0E2 = (M$-$1L$-$3T4A2)(MLT$-$3A$-$1)2

= M$-$1L$-$3T4A2M2L2T$-$6A$-$2 = ML$-$1T$-$2