1

IIT-JEE 2000 Screening

MCQ (Single Correct Answer)
The dimension of $$\left( {{1 \over 2}} \right){\varepsilon _0}{E^2}$$
( $${\varepsilon _0}$$ : permittivity of free space, E electric field )
A
MLT-1
B
ML2T-2
C
ML-1T-2
D
ML2T-1

Explanation

Dimension of $$\varepsilon $$0 = M$$-$$1L$$-$$3T4A2

Dimension of electric field E = MLT$$-$$3A$$-$$1

Now, dimension of

$${1 \over 2}$$$$\varepsilon $$0E2 = (M$$-$$1L$$-$$3T4A2)(MLT$$-$$3A$$-$$1)2

= M$$-$$1L$$-$$3T4A2M2L2T$$-$$6A$$-$$2 = ML$$-$$1T$$-$$2

Answer (C)

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