IIT-JEE 2011 Paper 2 Offline

MCQ (More than One Correct Answer)

-1

Let $$f:(0,1) \to R$$ be defined by $$f(x) = {{b - x} \over {1 - bx}}$$, where be is a constant such that $$0 < b < 1$$. Then

f is not invertible on (0, 1).

f $$\ne$$ f^$$-$$1 on (0, 1) and $$f'(b) = {1 \over {f'(0)}}$$.

f = f^$$-$$1 on (0, 1) and $$f'(b) = {1 \over {f'(0)}}$$.

f^$$-$$1 is differentiable on (0, 1).

JEE Advanced Subjects