MHT CET 2025 19th April Evening Shift | Simple Harmonic Motion Question 37 | Physics

If the length of the oscillating simple pendulum is made $\frac{1}{3}$ times the original keeping amplitude same then increase in its total energy at a place will be

3 times

2 times

9 times

5 times

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

The time period of a simple pendulum inside a stationary lift is $\sqrt{3}$ second. When the lift moves upwards with an acceleration $g / 3$, the time period will be ( $\mathrm{g}=$ acceleration due to gravity)

1.5 s

2 s

$\sqrt{3} \mathrm{~s}$

3 s

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

A mass suspended from a vertical spring performs S.H.M. of period 0.1 second. The spring is unstretched at the highest point of suspension. Maximum speed of the mass is (Gravitational acceleration $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )

$\frac{1}{2 \pi} \mathrm{~m} / \mathrm{s}$

$\frac{1}{\pi} \mathrm{~m} / \mathrm{s}$

$\frac{2}{\pi} \mathrm{~m} / \mathrm{s}$

$\pi \mathrm{m} / \mathrm{s}$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

' $P$ ' and ' $Q$ ' are fixed points in same plane and mass ' $m$ ' is tied by string as shown in figure. If the mass is displaced slightly out of this plane and released, it will oscillate with time period $(\mathrm{PQ}=2 \mathrm{~d}, \mathrm{PR}=\mathrm{QR}=\mathrm{L})(\mathrm{g}=$ gravitational acceleration)

MHT CET 2025 19th April Morning Shift Physics - Simple Harmonic Motion Question 36 English

$2 \pi \sqrt{\frac{\mathrm{~L}}{\mathrm{~g}}}$

$2 \pi \sqrt{\frac{\mathrm{~L}^2}{\mathrm{~g}}}$

$2 \pi \sqrt{\frac{\left(L^2-d^2\right)^{1 / 2}}{g}}$

$2 \pi \sqrt{\frac{\left(L^2+d^2\right)^{1 / 2}}{g}}$

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