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MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

For a particle performing; S.H.M. the displacement - time graph is shown.

MHT CET 2025 19th April Evening Shift Physics - Simple Harmonic Motion Question 23 English 1

For that particle the force - time graph is correctly shown in graph

MHT CET 2025 19th April Evening Shift Physics - Simple Harmonic Motion Question 23 English 2
A
(a)
B
(b)
C
(c)
D
(d)
2
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+1
-0

If the length of the oscillating simple pendulum is made $\frac{1}{3}$ times the original keeping amplitude same then increase in its total energy at a place will be

A
3 times
B
2 times
C
9 times
D
5 times
3
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
The time period of a simple pendulum inside a stationary lift is $\sqrt{3}$ second. When the lift moves upwards with an acceleration $g / 3$, the time period will be ( $\mathrm{g}=$ acceleration due to gravity)
A
1.5 s
B
2 s
C
$\sqrt{3} \mathrm{~s}$
D
3 s
4
MHT CET 2025 19th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
A mass suspended from a vertical spring performs S.H.M. of period 0.1 second. The spring is unstretched at the highest point of suspension. Maximum speed of the mass is (Gravitational acceleration $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )
A
$\frac{1}{2 \pi} \mathrm{~m} / \mathrm{s}$
B
$\frac{1}{\pi} \mathrm{~m} / \mathrm{s}$
C
$\frac{2}{\pi} \mathrm{~m} / \mathrm{s}$
D
$\pi \mathrm{m} / \mathrm{s}$
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