MHT CET 2021 22th September Evening Shift | Simple Harmonic Motion Question 41 | Physics

A body of mass '$$m$$' performs linear S.H.M. given by equation $$x=P \sin \omega t+Q \sin \left(\omega t+\frac{\pi}{2}\right)$$. The total energy of the particle at any instant is

$$\frac{1}{2} \mathrm{~m} \omega^2 \mathrm{PQ}$$

$$\frac{1}{2} \frac{\mathrm{m} \omega^2}{\mathrm{P}^2 \mathrm{Q}^2}$$

$$\frac{1}{2} m \omega^2\left(P^2+Q^2\right)$$

$$\frac{1}{2} m \omega^2 p^2 Q^2$$

MHT CET 2021 22th September Morning Shift

MCQ (Single Correct Answer)

-0

A mass $$0.4 \mathrm{~kg}$$ performs S.H.M. with a frequency $$\frac{16}{\pi} \mathrm{Hz}$$. At a certain displacement it has kinetic energy $$2 \mathrm{~J}$$ and potential energy $$1.2 \mathrm{~J}$$. The amplitude of oscillation is

$$0.15 \mathrm{~m}$$

$$0.125 \mathrm{~m}$$

$$0.075 \mathrm{~m}$$

$$0.1 \mathrm{~m}$$

MHT CET 2021 22th September Morning Shift

MCQ (Single Correct Answer)

-0

If the amplitude of linear S.H.M. is decreased then

its period and total energy will increase.

its period will increase and total energy will decrease

its period and total energy will decrease.

its period will not change but total energy will decrease

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

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A child is sitting on a swing which performs S.H.M. It has minimum and maximum heights from ground $$0.75 \mathrm{~cm}$$ and $$2 \mathrm{~m}$$ respectively. Its maximum speed will be $$\left[\mathrm{g}=10 \frac{\mathrm{m}}{\mathrm{s}^2}\right]$$

$$\sqrt{1.25} \mathrm{~m} / \mathrm{s}$$

$$\sqrt{12.5} \mathrm{~m} / \mathrm{s}$$

$$5 \mathrm{~m} / \mathrm{s}$$

$$25 \mathrm{~m} / \mathrm{s}$$

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