MHT CET 2021 22th September Evening Shift | Simple Harmonic Motion Question 31 | Physics

A body of mass '$$m$$' performs linear S.H.M. given by equation $$x=P \sin \omega t+Q \sin \left(\omega t+\frac{\pi}{2}\right)$$. The total energy of the particle at any instant is

$$\frac{1}{2} \mathrm{~m} \omega^2 \mathrm{PQ}$$

$$\frac{1}{2} \frac{\mathrm{m} \omega^2}{\mathrm{P}^2 \mathrm{Q}^2}$$

$$\frac{1}{2} m \omega^2\left(P^2+Q^2\right)$$

$$\frac{1}{2} m \omega^2 p^2 Q^2$$

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

-0

A child is sitting on a swing which performs S.H.M. It has minimum and maximum heights from ground $$0.75 \mathrm{~cm}$$ and $$2 \mathrm{~m}$$ respectively. Its maximum speed will be $$\left[\mathrm{g}=10 \frac{\mathrm{m}}{\mathrm{s}^2}\right]$$

$$\sqrt{1.25} \mathrm{~m} / \mathrm{s}$$

$$\sqrt{12.5} \mathrm{~m} / \mathrm{s}$$

$$5 \mathrm{~m} / \mathrm{s}$$

$$25 \mathrm{~m} / \mathrm{s}$$

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

-0

A pendulum clock is running fast. To correct its time, we should

reduce the mass of the bob.

reduce the amplitude of oscillation.

increase the length of the pendulum.

reduce the length of the pendulum.

MHT CET 2021 21th September Evening Shift

MCQ (Single Correct Answer)

-0

A particle is performing S.H.M. with maximum velocity '$$v$$'. If the amplitude is tripled and periodic time is doubled then maximum velocity will be

$$1.5 \mathrm{~v}$$

$$3 \mathrm{~v}$$

$$2 \mathrm{~v}$$

$$\mathrm{v}$$

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