1
IIT-JEE 2011 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
Let $$E$$ and $$F$$ be two independent events. The probability that exactly one of them occurs is $$\,{{11} \over {25}}$$ and the probability of none of them occurring is $$\,{{2} \over {25}}$$. If $$P(T)$$ denotes the probability of occurrence of the event $$T,$$ then
A
$$P\left( E \right) = {4 \over 5},P\left( F \right) = {3 \over 5}$$
B
$$P\left( E \right) = {1 \over 5},P\left( F \right) = {2 \over 5}$$
C
$$P\left( E \right) = {2 \over 5},P\left( F \right) = {1 \over 5}$$
D
$$P\left( E \right) = {3 \over 5},P\left( F \right) = {4 \over 5}$$
2
IIT-JEE 1999
MCQ (More than One Correct Answer)
+3
-0.75
The probabilities that a student passes in Mathematics, Physics and Chemistry are $$m, p$$ and $$c,$$ respectively. Of these subjects, the student has a $$75%$$ chance of passing in at least one, a $$50$$% chance of passing in at least two, and a $$40$$% chance of passing in exactly two. Which of the following relations are true?
A
$$p+m+c=19/20$$
B
$$p+m+c=27/20$$
C
$$pmc=1/10$$
D
$$pmc=1/4$$
3
IIT-JEE 1998
MCQ (More than One Correct Answer)
+2
-0.5
If $$\overline E$$ and $$\overline F$$ are the complementary events of events $$E$$ and $$F$$ respectively and if $$0 < P\left( F \right) < 1,$$ then
A
$$P\left( {E/F} \right) + P\left( {\overline E /F} \right) = 1$$
B
$$P\left( {E/F} \right) + P\left( {E/\overline F } \right) = 1$$
C
$$P\left( {\overline E /F} \right) + P\left( {E/\overline F } \right) = 1$$
D
$$P\left( {E/\overline F } \right) + P\left( {\overline E /\overline F } \right) = 1$$
4
IIT-JEE 1995 Screening
MCQ (More than One Correct Answer)
+2
-0.5
Let $$0 < P\left( A \right) < 1,0 < P\left( B \right) < 1$$ and
$$P\left( {A \cup B} \right) = P\left( A \right) + P\left( B \right) - P\left( A \right)P\left( B \right)$$ then
A
$$P\left( {B/A} \right) = P\left( B \right) - P\left( A \right)$$
B
$$P\left( {A' - B'} \right) = P\left( {A'} \right) - P\left( {B'} \right)$$
C
$$P\left( {A \cup B} \right)' = P\left( {A'} \right) - P\left( {B'} \right)$$
D
$$P\left( {A/B} \right) = P\left( A \right)$$
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