JEE Advanced 2017 Paper 2 Offline | Differential Equations Question 9 | Mathematics

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JEE Advanced 2017 Paper 2 Offline

MCQ (More than One Correct Answer)

-2

If $$g(x) = \int_{\sin x}^{\sin (2x)} {{{\sin }^{ - 1}}} (t)\,dt$$, then

$$g'\left( { - {\pi \over 2}} \right) = 0$$

$$g'\left( { - {\pi \over 2}} \right) = - 2\pi $$

$$g'\left( {{\pi \over 2}} \right) = 2\pi $$

$$g'\left( {{\pi \over 2}} \right) = 0$$

JEE Advanced 2016 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

A solution curve of the differential equation

$$\left( {{x^2} + xy + 4x + 2y + 4} \right){{dy} \over {dx}} - {y^2} = 0,$$ $$x>0,$$ passes through the

point $$(1,3)$$. Then the solution curve

intersects $$y=x+2$$ exactly at one point

intersects $$y=x+2$$ exactly at two points

intersects $$y = {\left( {x + 2} \right)^2}$$

does NOT intersect $$\,y = {\left( {x + 3} \right)^2}$$

JEE Advanced 2016 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

Let $$f:(0,\infty ) \to R$$ be a differentiable function such that $$f'(x) = 2 - {{f(x)} \over x}$$ for all $$x \in (0,\infty )$$ and $$f(1) \ne 1$$. Then

$$\mathop {\lim }\limits_{x \to {0^ + }} f'\left( {{1 \over x}} \right) = 1$$

$$\mathop {\lim }\limits_{x \to {0^ + }} xf\left( {{1 \over x}} \right) = 2$$

$$\mathop {\lim }\limits_{x \to {0^ + }} {x^2}f'(x) = 0$$

$$\left| {f(x)} \right| \le 2$$ for all $$x \in (0,2)$$

JEE Advanced 2015 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

Let $$y(x)$$ be a solution of the differential equation
$$\left( {1 + {e^x}} \right)y' + y{e^x} = 1.$$
If $$y(0)=2$$, then which of the following statement is (are) true?

$$y(-4)=0$$

$$y(-2)=0$$

$$y(x)$$ has a critical point in the interval $$(-1, 0)$$

$$y(x)$$ has no critical point in the interval $$(-1,0)$$

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