Evaluate :$$\,\,\int {\left[ {{{{{\left( {\cos 2x} \right)}^{1/2}}} \over {\sin x}}} \right]dx} $$
Answer
$${1 \over {\sqrt 2 }}\,\log \left[ {{{\sqrt 2 + \sqrt {1 - {{\tan }^2}x} } \over {\sqrt 2 - \sqrt {1 - {{\tan }^2}x} }}} \right] - \log \left( {\cot x + \sqrt {{{\cot }^2}x - 1} } \right) + C$$