IIT-JEE 2012 Paper 1 Offline | Heat and Thermodynamics Question 58 | Physics

IIT-JEE 2012 Paper 1 Offline

MCQ (Single Correct Answer)

-0.75

A mixture of 2 moles of helium gas (atomic mass = 4 amu) and 1 mole of argon gas (atomic mass = 40 amu) is kept at 300 K in a container. The ratio of the rms speeds $$\left( {{{{v_{rms}}\left( {helium} \right)} \over {{v_{rms}}\left( {\arg on} \right)}}} \right)$$ is

0.32

0.45

2.24

3.16

IIT-JEE 2012 Paper 1 Offline

MCQ (Single Correct Answer)

-1

Three very large plates of same area are kept parallel and close to each other. They are considered as ideal black surfaces and have very high thermal conductively. The first and third plates are maintained at temperatures 2T and 3T, respectively. The temperature of the middle (i.e. second) plate under steady state condition is

$${\left( {{{65} \over 2}} \right)^{1/4}}T$$

$${\left( {{{97} \over 4}} \right)^{1/4}}T$$

$${\left( {{{97} \over 2}} \right)^{1/4}}T$$

$${(97)^{1/4}}T$$

IIT-JEE 2011 Paper 2 Offline

MCQ (Single Correct Answer)

-1

One mole of a monatomic gas is taken through a cycle ABCDA as shown in the PV diagram. Column II give the characteristics involved in the cycle. Match them with each of the processes given in Column I.

IIT-JEE 2011 Paper 2 Offline Physics - Heat and Thermodynamics Question 35 English

	Column I		Column II
(A)	Process A$$ \to $$ B	(P)	Internal energy decreases.
(B)	Process B$$ \to $$C	(Q)	Internal energy increase.
(C)	Process C$$ \to $$D	(R)	Heat is lost.
(D)	Process D$$ \to $$A	(S)	Heat is gained.
		(T)	Work is done on the gas.

(A)$$\to$$(P), (R), (T); (B)$$\to$$(P), R; (C)$$\to$$(Q), (S); (D)$$\to$$(R), (T)

(A)$$\to$$(P), (T); (B)$$\to$$(P), (R); (C)$$\to$$(Q), (S); (D)$$\to$$(R)

(A)$$\to$$(R), (T); (B)$$\to$$(P), (R); (C)$$\to$$(S); (D)$$\to$$(R), (T)

(A)$$\to$$(P), (R), (T); (B)$$\to$$(P), (R); (C)$$\to$$(Q); (D)$$\to$$(R), (T)

IIT-JEE 2011 Paper 1 Offline

MCQ (Single Correct Answer)

-0.5

5.6 liter of helium gas at STP is adiabatically compressed to 0.7 liter. Taking the initial temperature to be T₁, the work done in the process is

$${9 \over 8}R{T_1}$$

$${3 \over 2}R{T_1}$$

$${15 \over 8}R{T_1}$$

$${9 \over 2}R{T_1}$$

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