1
IIT-JEE 2006
MCQ (Single Correct Answer)
+3
-0

Heat given to the processes is positive. Match Column I with Column II:

IIT-JEE 2006 Physics - Heat and Thermodynamics Question 5 English

Column I Column II
(A) JK (P) $$
\Delta W>0
$$
(B) KL (Q) $$
\Delta \mathrm{Q}<0
$$
(C) LM (R) $$
\Delta \mathrm{W}<0
$$
(D) MJ (S) $$
\Delta Q>0
$$

A

$$ [\mathrm{A} \rightarrow(\mathrm{Q}) ; \mathrm{B} \rightarrow(\mathrm{~S}) ; \mathrm{C} \rightarrow(\mathrm{Q}) ; \mathrm{D} \rightarrow( \mathrm{R})]$$

B

$$ [\mathrm{A} \rightarrow(\mathrm{Q}) ; \mathrm{B} \rightarrow(\mathrm{P}) ; \mathrm{C} \rightarrow(\mathrm{~S}) ; \mathrm{D} \rightarrow(\mathrm{Q})]$$

C

$$ [\mathrm{A} \rightarrow(\mathrm{Q}) ; \mathrm{B} \rightarrow(\mathrm{P}, \mathrm{~S}) ; \mathrm{C} \rightarrow(\mathrm{~S}) ; \mathrm{D} \rightarrow(\mathrm{Q}, \mathrm{R})] $$

D

$$ [\mathrm{A} \rightarrow(\mathrm{Q}) ; \mathrm{B} \rightarrow(\mathrm{S}) ; \mathrm{C} \rightarrow(\mathrm{S}) ; \mathrm{D} \rightarrow( \mathrm{R})]$$

2
IIT-JEE 2005 Mains
MCQ (Single Correct Answer)
+3
-1

A cylinder of mass $$1 \mathrm{~kg}$$ is given heat of $$20000 \mathrm{~J}$$ at atmospheric pressure. If initially temperature of cylinder is $$20^{\circ} \mathrm{C}$$, find

(A) The final temperature of the cylinder;

(B) The work done by the cylinder;

(C) The change in internal energy of the cylinder.

Given :

The specific heat of cylinder

$$=400 \mathrm{~J} \mathrm{~kg}^{-1 \circ} \mathrm{C}^{-1}$$

Coefficient of volume expansion

$$=9 \times 10^{-5}{ }^{\circ} \mathrm{C}^{-1} \text {; }$$

Atmospheric pressure $$=10^{5} \mathrm{~N} / \mathrm{m}^{2}$$ Density of cylinder $$=9000 \mathrm{~kg} / \mathrm{m}^{3}$$ )

A
$$(\mathrm{A}) 70^{\circ} \mathrm{C}$$, (B) $$0.05 \mathrm{~J}$$ (C) $$\Delta \mathrm{U}=1.9 \times 10^{4} \mathrm{~J}$$
B
$$(\mathrm{A}) 70^{\circ} \mathrm{C}$$, (B) $$0.05 \mathrm{~J}$$ (C) $$\Delta \mathrm{U}=2.9 \times 10^{4} \mathrm{~J}$$
C
$$(\mathrm{A}) 60^{\circ} \mathrm{C}$$, (B) $$0.05 \mathrm{~J}$$ (C) $$\Delta \mathrm{U}=1.9 \times 10^{4} \mathrm{~J}$$
D
$$(\mathrm{A}) 70^{\circ} \mathrm{C}$$, (B) $$0.07 \mathrm{~J}$$ (C) $$\Delta \mathrm{U}=1.9 \times 10^{4} \mathrm{~J}$$

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