IIT-JEE 1989 | Permutations and Combinations Question 34 | Mathematics

IIT-JEE 1989

MCQ (Single Correct Answer)

-0.5

A five-digit numbers divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 and 5, without repetition. The total number of ways this can be done is

216

240

600

3125

IIT-JEE 1982

MCQ (Single Correct Answer)

-0.5

Ten different letters of an alphabet are given. Words with five letters are formed from these given letters. Then the numbers of words which have at least one letter repeated are

69760

30240

99748

none of these

IIT-JEE 1982

MCQ (Single Correct Answer)

-0.5

Eight chairs are numbered 1 to 8. Two women and three men wish to occupy one chair each. First the women choose the chairs from amongst the chairs marked 1 to 4; and then the men select the chairs from amongst the remaining. The number of possible arrangements is

$${}^6{C_3} \times {}^4{C_2}$$

$${}^4{P_2} \times {}^4{P_3}$$

$${}^4{C_2} \times {}^4{P_3}$$

none of these

IIT-JEE 1982

MCQ (Single Correct Answer)

-0.5

The value of the expression $$\,{}^{47}{C_4} + \sum\limits_{j = 1}^5 {^{52 - j}\,{C_3}} $$ is equal to

$${}^{47}{C_5}$$

$${}^{52}{C_5}$$

$${}^{52}{C_4}$$

none of these