GATE ECE 2011 | Transient Response Question 15 | Network Theory

GATE ECE 2011

MCQ (Single Correct Answer)

-0.6

In the circuit shown below, the initial charge on the capacitor is 2.5 mC, with the voltage polarity as indicated. The switch is closed at time t=0. The current i(t) at a time t after the switch is closed is

GATE ECE 2011 Network Theory - Transient Response Question 22 English

i(t) = 15 exp(-2 × 10³ t) A

i(t) = 5 exp(-2 × 10³ t) A

i(t) = 10 exp(-2 × 10³ t) A

i(t) = -5 exp(-2 × 10³ t) A

GATE ECE 2010

MCQ (Single Correct Answer)

-0.6

In the circuit shown, the switch S is open for a long time and is closed at t=0. The current i(t) for t ≥ 0⁺ is GATE ECE 2010 Network Theory - Transient Response Question 17 English

GATE ECE 2010 Network Theory - Transient Response Question 17 English

i(t) = 0.5 - 0.125e^-1000t A

i(t) = 1.5 - 0.125e^-1000t A

i(t) = 0.5 - 0.5e^-1000t A

i(t) = 0.375e^-1000t A

GATE ECE 2009

MCQ (Single Correct Answer)

-0.6

The time domain behavior of an RL circuit is represented by $$$\mathrm L\frac{\mathrm{di}\left(\mathrm t\right)}{\mathrm{dt}}+\mathrm{Ri}\;=\;{\mathrm V}_0\left(1\;+\;\mathrm{Be}^{-\mathrm{Rt}/\mathrm L}\;\sin\;\mathrm t\right)\mathrm u\left(\mathrm t\right)$$$ For an initial current of i(0) = $$\frac{{\mathrm V}_0}{\mathrm R}$$, the steady state value of the current is given by

$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{{\mathrm V}_0}{\mathrm R}$$

$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{2{\mathrm V}_0}{\mathrm R}$$

$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{{\mathrm V}_0}{\mathrm R}\left(1+\mathrm B\right)$$

$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{2{\mathrm V}_0}{\mathrm R}\left(1+\mathrm B\right)$$

GATE ECE 2009

MCQ (Single Correct Answer)

-0.6

The switch in the circuit shown was on position ‘a’ for a long time and is moved to position ‘b’ at time t = 0. The current i(t) for t > 0 is given by GATE ECE 2009 Network Theory - Transient Response Question 19 English