1
GATE ECE 2003
+2
-0.6
An input voltage $$v(t)$$ $$= 10\sqrt 2 \,\,\cos \,\,\left( {t + {{10}^0}} \right) + 10\sqrt 5 \,\,\cos \left( {2t + {{10}^0}} \right)\,\,V$$ is applied to a series combination of resistance $$L = 1H$$. the resulting steady - state current $$i(t)$$ in ampere is
A
$$10\cos \left( {t + {{55}^0}} \right) + 10\,\cos \left( {2t + {{10}^0} + {{\tan }^{ - 1}}\,2} \right)$$
B
$$10\cos \left( {t + {{55}^0}} \right) + 10\sqrt {{3 \over 2}} \,\cos \left( {2t + {{55}^0}} \right)$$
C
$$10\cos \left( {t - {{35}^0}} \right) + 10\cos \left( {2t + {{10}^0} - {{\tan }^{ - 1}}\,2} \right)$$
D
$$10\cos \left( {t - {{35}^0}} \right) + 10\sqrt {{3 \over 2}} \,\cos \left( {2t - {{35}^0}} \right)$$
2
GATE ECE 2002
+2
-0.6
If the 3-phase balanced source in Fig. delivers 1500 W at a leading power factor of 0.844, then the value of ZL (in ohm) is approximately A
$$90\angle32.44^\circ$$
B
$$80\angle32.44^\circ$$
C
$$80\angle-32.44^\circ$$
D
$$90\angle-32.44^\circ$$
3
GATE ECE 2001
+2
-0.6
When the angular frequency $$\omega$$ in Fig. is varied from $$0$$ to $$\infty$$ the locus of the current phasor $${{\rm I}_2}$$ is given by     A
Fig. (i)
B
Fig. (ii)
C
Fig. (iii)
D
Fig. (iv)
4
GATE ECE 2000
+2
-0.6
In Fig., the steady state output voltage corresponding to the input voltage $$\left( {3 + 4\sin \,\,100\,t} \right)$$ $$V$$ is A
$$3 + {4 \over {\sqrt 2 }}\sin \left( {100\,t - {\pi \over 4}} \right)\,\,V$$
B
$$3 + 4\sqrt 2 \sin \left( {100\,t - {\pi \over 4}} \right)\,\,V$$
C
$${3 \over 2} + {4 \over {\sqrt 2 }}\sin \left( {100\,t + {\pi \over 4}} \right)\,\,V$$
D
$$3 + 4\sin \left( {100\,t - {\pi \over 4}} \right)\,\,V$$
GATE ECE Subjects
Signals and Systems
Network Theory
Control Systems
Digital Circuits
General Aptitude
Electronic Devices and VLSI
Analog Circuits
Engineering Mathematics
Microprocessors
Communications
Electromagnetics
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