1
MHT CET 2023 9th May Morning Shift
+1
-0

The maximum velocity of a particle performing S.H.M. is '$$\mathrm{V}$$'. If the periodic time is made $$\left(\frac{1}{3}\right)^d$$ and the amplitude is doubled, then the new maximum velocity of the particle will be

A
$$\frac{\mathrm{V}}{6}$$
B
$$\frac{3 \mathrm{~V}}{2}$$
C
$$3 \mathrm{~V}$$
D
$$6 \mathrm{~V}$$
2
MHT CET 2022 11th August Evening Shift
+1
-0

The time taken by a particle executing simple harmonic motion of period '$$\mathrm{T}$$', to move from the mean position to half the maximum displacement is

A
$$\frac{\mathrm{T}}{12} \mathrm{~s}$$
B
$$\frac{\mathrm{T}}{2} \mathrm{~s}$$
C
$$\frac{\mathrm{T}}{4} \mathrm{~s}$$
D
$$\frac{\mathrm{T}}{6} \mathrm{~s}$$
3
MHT CET 2022 11th August Evening Shift
+1
-0

In a medium, the phase difference between two particles separated by a distance '$$x$$' is $$\left(\frac{\pi}{5}\right)^{\text {c }}$$. If the frequency of the oscillation of particles is $$25 \mathrm{~Hz}$$ and the velocity of propagation of the waves is $$75 \mathrm{~m} / \mathrm{s}$$, then the value of $$x$$ is

A
0.4 m
B
0.1 m
C
0.2 m
D
0.3 m
4
MHT CET 2022 11th August Evening Shift
+1
-0

A particle starts oscillating simple harmonically from its mean position with time period '$$T$$'. At time $$t=\frac{T}{12}$$, the ratio of the potential energy to kinetic energy of the particle is $$\left(\sin 30^{\circ}=\cos 60^{\circ}=0.5, \cos 30^{\circ}=\sin 60^{\circ}=\sqrt{3} / 2\right)$$

A
$$1: 2$$
B
$$3: 1$$
C
$$2: 1$$
D
$$1: 3$$
EXAM MAP
Medical
NEET
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
CBSE
Class 12