1
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Four massless springs whose force constants are $$2 \mathrm{~K}, 2 \mathrm{~K}, \mathrm{~K}$$ and $$2 \mathrm{~K}$$ respectively are attached to a mass $$\mathrm{M}$$ kept on a frictionless plane as shown in figure, If mass $$M$$ is displaced in horizontal direction then frequency of oscillating system is

MHT CET 2023 12th May Morning Shift Physics - Simple Harmonic Motion Question 19 English

A
$$\frac{1}{2 \pi} \sqrt{\frac{\mathrm{K}}{4 \mathrm{M}}}$$
B
$$\frac{1}{2 \pi} \sqrt{\frac{4 \mathrm{~K}}{\mathrm{M}}}$$
C
$$\frac{1}{2 \pi} \sqrt{\frac{\mathrm{K}}{7 \mathrm{M}}}$$
D
$$\frac{1}{2 \pi} \sqrt{\frac{7 \mathrm{~K}}{\mathrm{M}}}$$
2
MHT CET 2023 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The upper end of the spring is fixed and a mass '$$m$$' is attached to its lower end. When mass is slightly pulled down and released, it oscillates with time period 3 second. If mass '$$\mathrm{m}$$' is increased by $$1 \mathrm{~kg}$$, the time period becomes 5 second. The value of '$$\mathrm{m}$$' is (mass of spring is negligible)

A
$$\frac{3}{8} \mathrm{~kg}$$
B
$$\frac{5}{9} \mathrm{~kg}$$
C
$$\frac{8}{13} \mathrm{~kg}$$
D
$$\frac{9}{16} \mathrm{~kg}$$
3
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For a particle executing S.H.M., its potential energy is 8 times its kinetic energy at certain displacement '$$x$$' from the mean position. If '$$A$$' is the amplitude of S.H.M the value of '$$x$$' is

A
$$\frac{\mathrm{A} \sqrt{2}}{3}$$
B
$$\mathrm{A} \sqrt{3}$$
C
$$\frac{2 \sqrt{2} \mathrm{~A}}{3}$$
D
$$\frac{\mathrm{A}}{\sqrt{2}}$$
4
MHT CET 2023 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The time period of a simple pendulum inside a stationary lift is '$$T$$'. When the lift starts accelerating upwards with an acceleration $$\left(\frac{\mathrm{g}}{3}\right)$$, the time period of the pendulum will be

A
$$\frac{\sqrt{5}}{2} \mathrm{~T}$$
B
$$\frac{\sqrt{3}}{2} \mathrm{~T}$$
C
$$\frac{2 \mathrm{~T}}{\sqrt{3}}$$
D
$$\frac{2 \mathrm{~T}}{\sqrt{5}}$$
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