1
MHT CET 2024 11th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

All the springs in fig. (a), (b) and (c) are identical, each having force constant K . Mass attached to each system is ' $m$ '. If $T_a, T_b$ and $T_c$ are the time periods of oscillations of the three systems respectively, then

MHT CET 2024 11th May Evening Shift Physics - Simple Harmonic Motion Question 5 English

A
$\mathrm{T}_{\mathrm{a}}=\sqrt{2} \mathrm{~T}_{\mathrm{b}}$
B
$\mathrm{T}_{\mathrm{a}}=\frac{\mathrm{T}_{\mathrm{c}}}{\sqrt{2}}$
C
$T_b=2 T_a$
D
$T_b=2 T_c$
2
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A simple pendulum of length ' $L$ ' has mass ' $M$ ' and it oscillates freely with amplitude ' $A$ '. At extreme position, its potential energy is

A
$\frac{\mathrm{MgA}^2}{\mathrm{~L}}$
B
$\frac{2 \mathrm{MgA}^2}{\mathrm{~L}}$
C
$\frac{\mathrm{MgA}}{2 \mathrm{~L}}$
D
$\frac{\mathrm{MgA}^2}{2 \mathrm{~L}}$
3
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle performing S.H.M. starts from equilibrium position and its time period is 12 second. After 2 seconds its velocity is $\pi \mathrm{m} / \mathrm{s}$. Amplitude of the oscillation is $\left[\sin 30^{\circ}=\cos 60^{\circ}=0 \cdot 5, \sin 60^{\circ}=\cos 30^{\circ}=\sqrt{3} / 2\right]$

A
6 m
B
12 m
C
$12 \sqrt{3} \mathrm{~m}$
D
$6 \sqrt{3} \mathrm{~m}$
4
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle performs linear S.H.M. at a particular instant, velocity of the particle is ' $u$ ' and acceleration is ' $\mathrm{a}_1$ ' while at another instant velocity is ' V ' and acceleration is ' $a_2$ ' $\left(0

A
$\frac{v^2-u^2}{a_1-a_2}$
B
$\frac{v^2+u^2}{a_1+a_2}$
C
$\frac{u^2+v^2}{a_1-a_2}$
D
$\frac{u^2-V^2}{a_1+a_2}$
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