1
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle starts oscillating simple harmonically from its mean position with time period '$$T$$'. At time $$t=\frac{T}{12}$$, the ratio of the potential energy to kinetic energy of the particle is $$\left(\sin 30^{\circ}=\cos 60^{\circ}=0.5, \cos 30^{\circ}=\sin 60^{\circ}=\sqrt{3} / 2\right)$$

A
$$1: 2$$
B
$$3: 1$$
C
$$2: 1$$
D
$$1: 3$$
2
MHT CET 2021 24th September Evening Shift
MCQ (Single Correct Answer)
+1
-0

The displacement of a particle performing S.H.M. is given by $$x=5 \sin (3 t+3)$$, where $$x$$ is in $$\mathrm{cm}$$ and $$t$$ is in second. The maximum acceleration of the particle will be

A
$$15 \mathrm{~cm} \mathrm{~s}^{-2}$$
B
$$30 \mathrm{~cm} \mathrm{~s}^{-2}$$
C
$$45 \mathrm{~cm} \mathrm{~s}^{-2}$$
D
$$90 \mathrm{~cm} \mathrm{~s}^{-2}$$
3
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

Two identical springs of constant '$$\mathrm{K}$$' are connected in series and parallel in shown in figure. A mass '$$\mathrm{M}$$' is suspended from them. The ratio of their frequencies is series to parallel combination will be

MHT CET 2021 24th September Morning Shift Physics - Simple Harmonic Motion Question 2 English

A
$$1: 2$$
B
$$1: 4$$
C
$$4: 1$$
D
$$1: \sqrt{2}$$
4
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle performing linear S.H.M. of amplitude $$0.1 \mathrm{~m}$$ has displacement $$0.02 \mathrm{~m}$$ and acceleration $$0.5 \mathrm{~m} / \mathrm{s}^2$$. The maximum velocity of the particle in $$\mathrm{m} / \mathrm{s}$$ is

A
0.05
B
0.50
C
0.01
D
0.25
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