MHT CET 2021 24th September Morning Shift | Simple Harmonic Motion Question 70 | Physics

A particle performing linear S.H.M. of amplitude $$0.1 \mathrm{~m}$$ has displacement $$0.02 \mathrm{~m}$$ and acceleration $$0.5 \mathrm{~m} / \mathrm{s}^2$$. The maximum velocity of the particle in $$\mathrm{m} / \mathrm{s}$$ is

0.05

0.50

0.01

0.25

MHT CET 2021 24th September Morning Shift

MCQ (Single Correct Answer)

-0

A body is executing S.H.M. under the action of force having maximum magntude $$50 \mathrm{~N}$$. When its energy is half kinetic and half potential; the magnitude of the force acting on the particle is

$$\frac{25}{\sqrt{2}} \mathrm{~N}$$

$$50 \mathrm{~N}$$

$$25 \mathrm{~N}$$

$$25 \sqrt{2} \mathrm{~N}$$

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

A bob of simple pendulum of mass 'm' perform $$\mathrm{SHM}$$ with amplitude '$$\mathrm{A}$$' and period 'T'. Kinetic energy of pendulum of displacement $$x=\frac{A}{2}$$ will be

$$\frac{2 \mathrm{~m} \pi^2 A}{3 \mathrm{~T}^2}$$

$$\mathrm{\frac{3 m \pi^2 A}{2 T}}$$

$$\frac{2 \mathrm{~m} \pi \mathrm{A}^2}{3 \mathrm{~T}}$$

$$\frac{2 \mathrm{~m} \pi^2 \mathrm{~A}^2}{2 \mathrm{~T}^2}$$

MHT CET 2021 23rd September Evening Shift

MCQ (Single Correct Answer)

-0

An object executes SHM along $$x$$-axis with amplitude $$0.06 \mathrm{~m}$$. At certain distance '$$\mathrm{x}$$' metre from mean position, it has kinetic energy $$10 \mathrm{~J}$$ and potential energy $$8 \mathrm{~J}$$. the distance '$$\mathrm{x}$$' will be

0.08 m

0.02 m

0.04 m

0.06 m

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