MHT CET 2023 9th May Evening Shift | Simple Harmonic Motion Question 23 | Physics

A particle is vibrating in S.H.M. with an amplitude of $$4 \mathrm{~cm}$$. At what displacement from the equilibrium position is its energy half potential and half kinetic?

$$1 \mathrm{~cm}$$

$$\sqrt{2} \mathrm{~cm}$$

$$2 \mathrm{~cm}$$

$$2 \sqrt{2} \mathrm{~cm}$$

MHT CET 2023 9th May Morning Shift

MCQ (Single Correct Answer)

-0

A rubber ball filled with water, having a small hole is used as the bob of a simple pendulum. The time period of such a pendulum

is a constant.

decreases with time.

increases with time.

first increases and then decreases, finally having same value as at the beginning.

MHT CET 2023 9th May Morning Shift

MCQ (Single Correct Answer)

-0

The maximum velocity of a particle performing S.H.M. is '$$\mathrm{V}$$'. If the periodic time is made $$\left(\frac{1}{3}\right)^d$$ and the amplitude is doubled, then the new maximum velocity of the particle will be

$$\frac{\mathrm{V}}{6}$$

$$\frac{3 \mathrm{~V}}{2}$$

$$3 \mathrm{~V}$$

$$6 \mathrm{~V}$$

MHT CET 2022 11th August Evening Shift

MCQ (Single Correct Answer)

-0

The time taken by a particle executing simple harmonic motion of period '$$\mathrm{T}$$', to move from the mean position to half the maximum displacement is

$$\frac{\mathrm{T}}{12} \mathrm{~s}$$

$$\frac{\mathrm{T}}{2} \mathrm{~s}$$

$$\frac{\mathrm{T}}{4} \mathrm{~s}$$

$$\frac{\mathrm{T}}{6} \mathrm{~s}$$

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