1
MHT CET 2023 9th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

A particle is vibrating in S.H.M. with an amplitude of $$4 \mathrm{~cm}$$. At what displacement from the equilibrium position is its energy half potential and half kinetic?

A
$$1 \mathrm{~cm}$$
B
$$\sqrt{2} \mathrm{~cm}$$
C
$$2 \mathrm{~cm}$$
D
$$2 \sqrt{2} \mathrm{~cm}$$
2
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A rubber ball filled with water, having a small hole is used as the bob of a simple pendulum. The time period of such a pendulum

A
is a constant.
B
decreases with time.
C
increases with time.
D
first increases and then decreases, finally having same value as at the beginning.
3
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The maximum velocity of a particle performing S.H.M. is '$$\mathrm{V}$$'. If the periodic time is made $$\left(\frac{1}{3}\right)^d$$ and the amplitude is doubled, then the new maximum velocity of the particle will be

A
$$\frac{\mathrm{V}}{6}$$
B
$$\frac{3 \mathrm{~V}}{2}$$
C
$$3 \mathrm{~V}$$
D
$$6 \mathrm{~V}$$
4
MHT CET 2022 11th August Evening Shift
MCQ (Single Correct Answer)
+1
-0

The time taken by a particle executing simple harmonic motion of period '$$\mathrm{T}$$', to move from the mean position to half the maximum displacement is

A
$$\frac{\mathrm{T}}{12} \mathrm{~s}$$
B
$$\frac{\mathrm{T}}{2} \mathrm{~s}$$
C
$$\frac{\mathrm{T}}{4} \mathrm{~s}$$
D
$$\frac{\mathrm{T}}{6} \mathrm{~s}$$
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