1
GATE ECE 1999
MCQ (Single Correct Answer)
+1
-0.3
The input to a channel is a band pass signal. It is obtained by linearly modulating a sinusoidal carrier with a signal- tone signal. The output of the channel due to this input is given by y(t) = (1/100) cos$$(100t - {10^{ - 6}})\,$$ cos$$({10^6}t - 1.56)$$. The group delay $$({t_g})$$ and the phase delay $$({t_p})$$, in seconds, of the channel are
A
$${t_g} = {10^{ - 6}},\,{t_p} = 1.56$$
B
$${t_g} = 1.56,\,\,{t_p} = {10^{ - 6}}$$
C
$${t_g} = \,\,{10^{ - 8}},\,\,{t_p} = 1.56 \times {10^{ - 6}}$$
D
$${t_g} = {10^{ - 8}},\,{t_p} = 1.56$$
2
GATE ECE 1996
MCQ (Single Correct Answer)
+1
-0.3
A rectangular pulse of duration T is applied to a filter matched to this input. The output of the filter is a
A
rectangular pulse of duration T.
B
rectangular pulse of duration 2T.
C
triangular pulse.
D
sine function.
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