1
GATE ECE 2005
+1
-0.3
In a series $$RLC$$ circuit $$R = 2\,k\Omega ,\,\,\,L = \,1H$$ and $$C = \,1/400\,\mu F.$$ The resonant frequency is
A
$$2 \times {10^4}\,Hz$$
B
$${1 \over \pi } \times {10^4}\,Hz$$
C
$${10^4}\,Hz$$
D
$$2\pi \times {10^4}\,Hz$$
2
GATE ECE 2004
+1
-0.3
The circuit shown in figure, with $$R = 1/3\Omega$$, $$L = 1/4H$$, $$C = 3F$$ has input voltage $$v\left( t \right) = \sin \,2t$$. The resulting current $$i(t)$$ is A
$$5\,\sin \left( {2t + {{53.1}^0}} \right)$$
B
$$5\,\sin \left( {2t - {{53.1}^0}} \right)$$
C
$$25\,\sin \left( {2t + {{53.1}^0}} \right)$$
D
$$25\,\sin \left( {2t - {{53.1}^0}} \right)$$
3
GATE ECE 2004
+1
-0.3
For the circuit shown in figure, the time constant $$RC = 1$$ $$ms$$. The input voltage is $${v_i}\left( t \right) = \sqrt 2 \,\sin \,{10^3}t$$. The output voltage $${v_0}\left( t \right)$$ is equal to A
$$\sin \left( {{{10}^3}t - {{45}^0}} \right)$$
B
$$\sin \left( {{{10}^3}t + {{45}^0}} \right)$$
C
$$\sin \left( {{{10}^3}t - {{53}^0}} \right)$$
D
$$\sin \left( {{{10}^3}t + {{53}^0}} \right)$$
4
GATE ECE 2003
+1
-0.3
A series RLC circuit has a resonance frequency of 1 kHz and a quality factor Q = 100. If each R, L and C is doubled from its original value, the new Q of the circuit is
A
25
B
50
C
100
D
200
GATE ECE Subjects
Network Theory
Control Systems
Electronic Devices and VLSI
Analog Circuits
Digital Circuits
Microprocessors
Signals and Systems
Communications
Electromagnetics
General Aptitude
Engineering Mathematics
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