1
JEE Advanced 2018 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
The desired product $$X$$ can be prepared by reacting the major product of the reactions in LIST-I with one or more appropriate reagents in LIST-II (given, order of migratory aptitude: aryl > alkyl > hydrogen)

JEE Advanced 2018 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 64 English
The correct option is
A
$$P - 1;Q - 2,3;R - 1,4;S - 2,4$$
B
$$P - 1,5;Q - 3,4;R - 4,5;S - 3$$
C
$$P - 1,5;Q - 3,4;R - 5;S - 2,4$$
D
$$P - 1,5;Q - 2,3;R - 1,5;S - 2,3$$
2
JEE Advanced 2018 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
LIST-I contains reactions and LIST-II contains major products.

JEE Advanced 2018 Paper 2 Offline Chemistry - Alcohols, Phenols and Ethers Question 21 English

Match the reaction in LIST-I with one or more products in LIST-II and choose the correct option.
A
$$P - 1,5;Q - 2;R - 3;S - 4$$
B
$$P - 1,4;Q - 2;R - 4;S - 3$$
C
$$P - 1,4;Q - 1,2;R - 3,4;S - 4$$
D
$$P - 4,5;Q - 4;R - 4;S - 3,4$$
3
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
Change Language
For the given compound $$X,$$ the total number of optically active stereoisomers is ____________.

JEE Advanced 2018 Paper 2 Offline Chemistry - Basics of Organic Chemistry Question 39 English 1

JEE Advanced 2018 Paper 2 Offline Chemistry - Basics of Organic Chemistry Question 39 English 2
Your input ____
4
JEE Advanced 2018 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2
Change Language
For any positive integer n, define

$${f_n}:(0,\infty ) \to R$$ as

$${f_n} = \sum\limits_{j = 1}^n {{{\tan }^{ - 1}}} \left( {{1 \over {1 + (x + j)(x + j - 1)}}} \right)$$

for all x$$ \in $$(0, $$\infty $$). (Here, the inverse trigonometric function tan$$-$$1 x assumes values in $$\left( { - {\pi \over 2},{\pi \over 2}} \right)$$). Then, which of the following statement(s) is (are) TRUE?
A
$$\sum\limits_{j = 1}^5 {{{\tan }^2}({f_j}(0)) = 55} $$
B
$$\sum\limits_{j = 1}^{10} {(1 + f{'_j}(0)){{\sec }^2}({f_j}(0)) = 10} $$
C
For any fixed positive integer n, $$\mathop {\lim }\limits_{x \to \infty } \tan ({f_n}(x)) = {1 \over n}$$
D
For any fixed positive integer n, $$\mathop {\lim }\limits_{x \to \infty } {\sec ^2}({f_n}(x)) = 1$$
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