1
JEE Advanced 2018 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
The correct option(s) to distinguish nitrate salts of $$M{n^{2 + }}$$ and $$C{u^{2 + }}$$ taken separately is (are)
A
$$M{n^{2 + }}$$ shows the characteristic green color in the flame test
B
Only $$C{u^{2 + }}$$ shows the formation of precipitate by passing $${H_2}S$$ in acidic medium
C
Only $$M{n^{2 + }}$$ shows the formation of precipitate by passing $${H_2}S$$ in faintly basic medium
D
$$C{u^{2 + }}/Cu$$ has higher reduction potential than $$M{n^{2 + }}/Mn$$ (measured under similar conditions)
2
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
Change Language
The total number of compounds having at least one bridging oxo group among the molecules given below is _________.

$${N_2}{O_3},{N_2}{O_5},$$ $${P_4}{O_6},{P_4}{O_7},$$ $${H_4}{P_2}{O_5},{H_5}{P_3}{O_{10}},$$ $${H_2}{S_2}{O_3},{H_2}{S_2}{O_5}$$
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3
JEE Advanced 2018 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
The correct option(s) regarding the complex

$${\left[ {Co\left( {en} \right){{\left( {N{H_3}} \right)}_3}\left( {{H_2}O} \right)} \right]^{3 + }}\,\,$$ $$\left( {en = {H_2}NC{H_2}C{H_2}N{H_2}} \right)$$ is (are)
A
It has two geometrical isomers
B
It will have three geometrical isomers if bidentate 'en' is replaced by two cyanide ligands
C
It is paramagnetic
D
It absorbs light at longer wavelength as compared to

$${\left[ {Co\left( {en} \right){{\left( {N{H_3}} \right)}_4}} \right]^{3 + }}$$
4
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
Change Language
To measure the quantity of $$MnC{l_2}$$ dissolved in an aqueous solution, it was completely converted to $$KMn{O_4}$$ using the reaction,

$$MnC{l_2} + {K_2}{S_2}{O_8} + {H_2}O \to KMn{O_4} + {H_2}S{O_4} + HCl$$ (equation not balanced).

Few drops of concentrated $$HCl$$ were added to this solution and gently warmed. Further, oxalic acid ($$225$$ $$mg$$) was added in portions till the colour of the permanganate ion disappeared. The quantity of $$MnC{l_2}$$ (in mg) present in the initial solution is ____________.

(Atomic weights in $$g\,\,mo{l^{ - 1}}:Mn = 55,Cl = 35.5$$ )
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