1
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
The surface of copper gets tarnished by the formation of copper oxide. $${N_2}$$ gas was passed to prevent the oxide formation during heating of copper at $$1250$$ $$K.$$ However, the $${N_2}$$ gas contains $$1$$ mole % of water vapor as impurity. The water vapor oxidises copper as per the reaction given below : $$2Cu\left( s \right) + {H_2}O\left( g \right) \to C{u_2}O\left( s \right) + {H_2}\left( g \right)$$

$${P_{H2}}$$ is the minimum partial pressure of $${H_2}$$ (in bar) needed to prevent the oxidation at $$1250$$ $$K.$$ The value of $$\ln \left( {{P_{H2}}} \right)$$ is ________.

Given: total pressure $$=1$$ bar, $$R$$ (universal gas constant ) $$=$$ $$8J{K^{ - 1}}\,\,mo{l^{ - 1}},$$ $$\ln \left( {10} \right) = 2.3.\,$$ $$Cu(s)$$ and $$C{u_2}O\left( s \right)$$ are naturally immiscible.

At $$1250$$ $$K:2Cu(s)$$ $$ + {\raise0.5ex\hbox{$\scriptstyle 1$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}{O_2}\left( g \right) \to C{u_2}O\left( s \right);$$ $$\Delta {G^ \circ } = - 78,000J\,mo{l^{ - 1}}$$

$${H_2}\left( g \right) + {\raise0.5ex\hbox{$\scriptstyle 1$} \kern-0.1em/\kern-0.15em \lower0.25ex\hbox{$\scriptstyle 2$}}{O_2}\left( g \right) \to {H_2}O\left( g \right);$$

$$\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$$ $$\Delta {G^ \circ } = - 1,78,000J\,mo{l^{ - 1}};$$ ($$G$$ is the Gibbs energy)
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2
JEE Advanced 2018 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2
The Fischer presentation of $$D$$-glucose is given below.

JEE Advanced 2018 Paper 2 Offline Chemistry - Biomolecules Question 14 English
The correct structure(s) of $$\beta $$-$$L$$-glucopyranose is (are) :
A
JEE Advanced 2018 Paper 2 Offline Chemistry - Biomolecules Question 14 English Option 1
B
JEE Advanced 2018 Paper 2 Offline Chemistry - Biomolecules Question 14 English Option 2
C
JEE Advanced 2018 Paper 2 Offline Chemistry - Biomolecules Question 14 English Option 3
D
JEE Advanced 2018 Paper 2 Offline Chemistry - Biomolecules Question 14 English Option 4
3
JEE Advanced 2018 Paper 2 Offline
Numerical
+3
-0
In the following reaction sequence, the amount of $$D$$ (in g) formed from $$10$$ moles of acetophenone is ___________.

(Atomic weights in $$g\,mo{l^{ - 1}}:H = 1,C = 12,$$ $$N = 14,O = 16,$$ $$Br = 80.$$. The yield (%) corresponding to the product in each step is given in the parenthesis)

JEE Advanced 2018 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 59 English
Your input ____
4
JEE Advanced 2018 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
Aniline reacts with mixed acid (conc. $$HN{O_3}$$ and conc. $${H_2}S{O_4}$$) at $$288$$ $$K$$ to give P $$\left( {51\% } \right),$$ Q $$\left( {47\% } \right)$$ and R $$\left( {2\% } \right).$$ The major product(s) of the following reaction sequence is (are)

JEE Advanced 2018 Paper 2 Offline Chemistry - Compounds Containing Nitrogen Question 25 English
A
JEE Advanced 2018 Paper 2 Offline Chemistry - Compounds Containing Nitrogen Question 25 English Option 1
B
JEE Advanced 2018 Paper 2 Offline Chemistry - Compounds Containing Nitrogen Question 25 English Option 2
C
JEE Advanced 2018 Paper 2 Offline Chemistry - Compounds Containing Nitrogen Question 25 English Option 3
D
JEE Advanced 2018 Paper 2 Offline Chemistry - Compounds Containing Nitrogen Question 25 English Option 4
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