1
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of $|\bar{a} \cdot \bar{b}|^2 + |\bar{a} \times \bar{b}| \cdot |\bar{a} \times \bar{b}|$ is $\ldots$
A
$-a^2 b^2$
B
$a^2 b^2$
C
$a^2 b^2 \cos\theta$
D
$a^2 b^2 \sin\theta$
2
MHT CET 2026 18th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\bar{a} \cdot \bar{b} = \beta$ and $\bar{a} \times \bar{b} = \bar{c}$ then $\bar{a} = $
A
$\dfrac{\bar{b} \times \bar{c} - \beta\bar{b}}{|\bar{b}|^2}$
B
$\dfrac{\bar{b} \times \bar{c} - \beta\bar{c}}{|\bar{b}|^2}$
C
$\dfrac{\bar{b} \times \bar{c} + \beta\bar{b}}{|\bar{b}|^2}$
D
$\dfrac{\bar{b} \times \bar{c} + \beta\bar{c}}{|\bar{b}|^2}$
3
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $\bar{a} = \hat{i} - \hat{k}$, $\bar{b} = x\hat{i} + \hat{j} + (1-x)\hat{k}$ and $\bar{c} = y\hat{i} + x\hat{j} + (1+x-y)\hat{k}$ then $[\bar{a}\ \bar{b}\ \bar{c}]$ depends on
A
only x
B
neither x nor y
C
either x or y
D
only y
4
MHT CET 2026 18th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Let $\bar{u}, \bar{v}, \bar{w}$ be three vectors such that $|\bar{u}| = 1, |\bar{v}| = 2, |\bar{w}| = 3$. If the projection of $\bar{v}$ along $\bar{u}$ is equal to the projection of $\bar{w}$ along $\bar{u}$ and $\bar{v}, \bar{w}$ are perpendicular to each other, then $|\bar{u} - \bar{v} + \bar{w}| = $...
A
$4$
B
$\sqrt{7}$
C
$2$
D
$\sqrt{14}$

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