1
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The solution of the differential equation $e^{-x}(y+1)\text{d}y + (\cos^2 x - \sin 2x)y\, \text{d}x = 0$, given that $y = 1$ when $x = 0$ is
A
$\log y + \dfrac{1}{y} + e^x \cos^2 x = 1$
B
$\log y + y + e^x\cos^2 x = 2$
C
$(y+1) + e^x\cos^2 x = 2$
D
$\log\left(y + \dfrac{1}{y}\right) + e^x\cos^2 x = 1$
2
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The solution of the differential equation $\dfrac{dy}{dx} = e^{x-y} + x^2 e^{-y}$ is...
A
$y = e^x + c$
B
$e^y = e^x + x^3 + c$
C
$e^y = e^x + \dfrac{x^3}{3} + c$
D
$e^y = e^x + 2x + c$
3
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If the differential equation $\begin{vmatrix} f(x) & f'(x) \\ f'(x) & f''(x) \end{vmatrix} = 0$ for all $x$ and $f(0) = 1, f'(0) = 2$, then...
A
$f'(x) = -f(x)$
B
$f'(x) = f(x)$
C
$f'(x) = 2f(x)$
D
$f'(x) = 0$
4
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The solution of the differential equation $x^2 \dfrac{dy}{dx} - xy = 1$ is...
A
$2xy - 2cx^2 - 1 = 0$
B
$2xy + 2cx^2 + 1 = 0$
C
$2xy - 2cx^2 + 1 = 0$
D
$2x^2 y - 2cx + 1 = 0$

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