1
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation obtained from the function $$y=a(x-a)^2$$ is

A
$$8 y^2=\left(\frac{d y}{d x}\right)^2\left[x+\frac{1}{4 y}\left(\frac{d y}{d x}\right)^2\right]^2$$
B
$$4 y^2=\left(\frac{d y}{d x}\right)^2\left[x-\frac{1}{4 y}\left(\frac{d y}{d x}\right)^2\right]^2$$
C
$$2 y^2=\left(\frac{d y}{d x}\right)^2\left[x-\frac{1}{4 y}\left(\frac{d y}{d x}\right)^2\right]^2$$
D
$$8 y^2=\left(\frac{d y}{d x}\right)^2\left[x-\frac{1}{4 y}\left(\frac{d y}{d x}\right)^2\right]^2$$
2
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation of all lines perpendicular to the line $$5 x+2 y+7=0$$ is

A
$$2 d y-5 d x=0$$
B
$$5 d y-2 d x=0$$
C
$$2 d y-3 d x=0$$
D
$$3 d y-2 d x=0$$
3
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

The bacteria increases at the rate proportional to the number of bacteria present. If the original number '$$N$$' doubles in $$4 \mathrm{~h}$$, then the number of bacteria in $$12 \mathrm{~h}$$ will be

A
4N
B
8N
C
6N
D
3N
4
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

The rate of decay of certain substance is directly proportional to the amount present at that instant. Initially, there are $$27 \mathrm{~gm}$$ of certain substance and $$3 \mathrm{~h}$$ later it is found that $$8 \mathrm{~gm}$$ are left, then the amount left after one more hour is

A
$$\frac{20}{3} \mathrm{~gm}$$
B
$$\frac{16}{3} \mathrm{~gm}$$
C
$$\frac{19}{3} \mathrm{~gm}$$
D
$$\frac{17}{3} \mathrm{~gm}$$
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