1
MHT CET 2025 21st April Evening Shift
MCQ (Single Correct Answer)
+2
-0

A particular solution of $3 \mathrm{e}^x \tan y \mathrm{~d} x+\left(1-\mathrm{e}^x\right) \sec ^2 y \mathrm{~d} y=0$ with $y(1)=\frac{\pi}{4}$ is

A
$\quad \tan y=\left(\frac{1-\mathrm{e}^3}{1-\mathrm{e}^x}\right)^3$
B
$\quad \tan y=\left(\frac{1-\mathrm{e}^2}{1-\mathrm{e}^x}\right)^3$
C
$\quad \tan y=\left(\frac{1-\mathrm{e}}{1-\mathrm{e}^x}\right)^3$
D
$\quad \tan y=\left(\frac{1-\mathrm{e}^x}{1-\mathrm{e}}\right)^3$
2
MHT CET 2025 21st April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the curve passing through the origin and satisfying the equation $\left(1+x^2\right) \frac{\mathrm{d} y}{\mathrm{~d} x}+2 x y=4 x^2$, is

A
$3\left(1+x^2\right) y=4 x^3$
B
$3\left(1-x^2\right) y=4 x^3$
C
$3\left(1+x^2\right)=x^3$
D
$\quad 4\left(1-x^2\right)=x^3$
3
MHT CET 2025 21st April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation of all circles having their centres on the line $y=5$ and touching ( X -axis) is $\qquad$

A
$\quad(5-y) \frac{\mathrm{d} y}{\mathrm{~d} x}+y^2-10 y=0$
B
$\quad(5-y)^2 \frac{\mathrm{~d}^2 y}{\mathrm{~d} x^2}+y^2-10 y=0$
C
$\quad(5-y) \frac{\mathrm{d} y}{\mathrm{~d} x}+y-10=0$
D
$\quad(5-y)^2\left(\frac{\mathrm{~d} y}{\mathrm{~d} x}\right)^2+y^2-10 y=0$
4
MHT CET 2025 21st April Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a culture bacteria count is $1,00,000$ initially. The number increases by $10 \%$ in first 2 hours. In how many hours will the count reach $2,00,000$, if the rate of growth of bacteria is proportional to the number present?

A
$\frac{2 \log \left(\frac{11}{10}\right)}{\log 2}$
B
$\frac{\log \left(\frac{11}{10}\right)}{\log 2}$
C
$\frac{2 \log 2}{\log \left(\frac{11}{10}\right)}$
D
$\frac{\log (2)}{\log \left(\frac{11}{10}\right)}$
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