1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The general solution of the differential equation $\sec y + (x - e^{\sin y})\dfrac{dy}{dx} = 0$ is...
A
$e^{\sin y} = x + c$
B
$xe^{\sin y} = \dfrac{e^{2\sin y}}{2} + c$
C
$2x\cos y = e^x + c$
D
$\sin y - e^{\sin y} = c$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The general solution of the differential equations $\dfrac{dy}{dx} = (9x + y + 5)^2$ is...
A
$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = -2x + c$
B
$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = 2x + c$
C
$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = -3x + c$
D
$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = 3x + c$
3
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The tangent to the curve intersects the Y-axis at point P. A line drawn through point P is perpendicular to this tangent and passes through another point $(1, 0)$. The differential equation of the curve is...
A
$y\dfrac{dy}{dx} - x\left(\dfrac{dy}{dx}\right)^2 = 1$
B
$x\dfrac{dy}{dx} - y\left(\dfrac{dy}{dx}\right)^2 = 1$
C
$y\dfrac{dy}{dx} + x = 1$
D
$x\dfrac{dy}{dx} + y = 1$
4
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $y = e^{-mx}$ is a solution of the differential equation $\dfrac{d^2y}{dx^2} + 4\dfrac{dy}{dx} + 3y = 0$, then the values of $m$ are
A
$1, 3$
B
$-1, 3$
C
$-1, -3$
D
$1, -3$

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