1
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The general solution of

$x(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}=x^3(2 x-1)+(x-2) y$ is

A
$y(x-1)=x^3+\mathrm{c}(x-1)$, where c is the constant of integration.
B
$y=x^3(x-1)+\mathrm{c}$, where c is the constant of integration.
C
$y(x-1)=x^3(x-1)+\mathrm{cx}^2$, where c is the constant of integration.
D
$y(x-1)=x^3(x-1)+\mathrm{c}$, where c is the constant of integration.
2
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The money invested in a company is compounded continuously. ₹ 400 invested today becomes ₹ 800 in 6 years, then at the end of 33 years, it will become .. $(\sqrt{2}=1.4142)$

A
9050.88
B
18101.76
C
6788.16
D
12067.84
3
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The sum of the degree and order of the differential equation $\sqrt{\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}}=\sqrt[5]{\frac{\mathrm{d} y}{\mathrm{~d} x}-5}$ is

A
1
B
3
C
5
D
7
4
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation whose solution represents the family $x^2 y=4 \mathrm{e}^x+\mathrm{c}$, where c is an arbitrary constant, is

A
$\quad x \frac{\mathrm{~d} y}{\mathrm{~d} x}+x y=0$
B
$\quad x^2 \frac{\mathrm{~d} y}{\mathrm{~d} x}+(2 x-x y)=0$
C
$x \frac{\mathrm{~d} y}{\mathrm{~d} x}+(x-2) y=0$
D
$x^2 \frac{\mathrm{~d} y}{\mathrm{~d} x}+2 x y-4 \mathrm{e}^x=0$
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